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Sunny_sXe [5.5K]
3 years ago
7

Assume that a uniform magnetic field is directed into thispage. If an electron is released with an initial velocity directedfrom

the bottom edge to the top edge of the page, which of thefollowing describes the direction of the resultant force acting onthe electron?
A. out of the page
B. to the right
C. to the left
D. into the page
Physics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

B). to the right

Explanation:

Since the direction of magnetic field is into the page

So here we know that

B = B_o(-\hat k)

now the velocity is from bottom to top

so we have

v = v_o \hat j

now the force on the moving charge is given as

\vec F = q(\vec v \times \vec B)

now we have

\vec F = (-e)(v_o \hat j \times B_o(-\hat k))

\vec F = e v_o B \hat i

so force will be towards Right

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Which describes reproducibility? The ability of data to be published. The ability of data to be duplicated. The ability of data
olasank [31]

Answer:

the ability of data to be duplicated well described reproducibility

Explanation:

Reproducibitity of a data is the ability of a data to be produced in multiple times using the same procedure. It is used to test how precise a data is and it's usually known as standard deviation

Reproducibility is the closeness of the understanding between the consequences of measurements of the equivalent measurand did with a similar procedure depicted in the relating logical proof (for example a distribution in a companion surveyed diary).

3 0
3 years ago
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A ball is dropped from rest at a point 12 m above the ground into a smooth, frictionless chute. The ball exits the chute 2 m abo
Nonamiya [84]

Answer:

29,7 m

Explanation:

We need to devide the problem in two parts:

A)  Energy

B) MRUV

<u>Energy:</u>

Since no friction between pint (1) and (2), then the energy conservatets:

Energy = constant ----> Ek(cinética) + Ep(potencial) = constant

Ek1 + Ep1 = Ek2 + Ep2

Ek1 = 0  ; because V1 is zero (the ball is "dropped")

Ep1 = m*g*H1

Ep2= m*g*H2

Then:

Ek2  = m*g*(H1-H2)

By definition of cinetic energy:

m*(V2)²/2 = m*g*(H1-H2) --->  V2 = \sqrt{(2*g*(H1-H2)}

Replaced values:  V2 = 14,0 m/s

<u>MRUV:</u>

The decomposition of the velocity (V2), gives a for the horizontal component:

V2x = V2*cos(α)

Then the traveled distance is:

X = V2*cos(α)*t.... but what time?

The time what takes the ball hit the ground.

Since: Y3 - Y2 = V2*t + (1/2)*(-g)*t²

In the vertical  axis:

Y3 = 0 ; Y2 = H2 = 2 m

Reeplacing:

-2 = 14*t + (1/2)*(-9,81)*t²

solving the ecuation, the only positive solution is:

t = 2,99 sec ≈ 3 sec

Then, for the distance:

X = V2*cos(α)*t = (14 m/s)*(cos45°)*(3sec) ≈ 29,7 m

6 0
3 years ago
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The splitting of light into its component parts is referred to as which of the following?
natita [175]

Answer:

you would use a prism which refracts the light

because Light changes speed as it moves from one medium to another (for example, from air into the glass of the prism). This speed change causes the light to be refracted and to enter the new medium at a different angle (Huygens principle). The degree of bending of the light's path depends on the angle that the incident beam of light makes with the surface, and on the ratio between the refractive indices of the two media (Snell's law). The refractive index of many materials (such as glass) varies with the wavelength or color of the light used, a phenomenon known as dispersion. This causes light of different colors to be refracted differently and to leave the prism at different angles, creating an effect similar to a rainbow. This can be used to separate a beam of white light into its constituent spectrum of colors.

5 0
2 years ago
A voltmeter has an internal resistance of 10 000 Ω and is used to measure the voltage across a 47.0-Ω resistor that, without the
otez555 [7]

Answer:

b. 5.6 mA

Explanation:

As the voltmeter is connected to the resistor in parallel. The new resistance of the systems is

\frac{1}{R} = \frac{1}{r_1} + \frac{1}{r_2} = \frac{1}{10000} + \frac{1}{47} = 0.0214

R = 1/0.0214 = 46.78 Ω

The voltage is

U = r_2 I_1 = 47 * 1.2 = 56.4 V

So the new current now of the system is

I_2 = U/R = 56.4/46.78 = 1.2056 A

So about 1.2056 - 1.2 = 0.0056 A or 5.6mA is drawn away.

7 0
3 years ago
A billiard ball traveling at 3.4 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at re
Tpy6a [65]

Answer:

Explanation:

Given

Initial velocity of first billiard ball u_1=3.4\ m/s

Initial velocity of second billiard ball u_2=0\ m/s

After collision first ball comes to rest

suppose m is the mass of both the balls

Conserving momentum to get the speed of second ball after collision

Initial momentum P_i=mu_1+mu_2=m\cdot 3.4+0

Final momentum P_f=mv_1+mv_2

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P_i=P_f

m\cdot 3.4+0=0+m\cdot v_2

v_2=3.4\ m/s

thus speed of second ball after collision is equal to speed of first ball before collision

3 0
2 years ago
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