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3 years ago

Plsss someone help me pls!!! PART B: identify congruent angles

Mathematics

1 answer:

Westkost [7]3 years ago

6 0

Answer:

∠R=∠C

∠U=∠A

∠G=∠R

∴∠RUG=∠CAR

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Q2) for both of the following, calculate A5 and A100. (i) An= 6n-3

dlinn [17]

Answer:

27 and 597

Step-by-step explanation:

To evaluate A5 and A100, substitute n = 5, n = 100 into An , that is

A5 = 6(5) - 3 = 30 - 3 = 27

A100 = 6(100) - 3 = 600 - 3 = 597

4 0

3 years ago

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A puzzle contains a triangular piece with a base of 3 in. and a height of 4 in. A manufacturer wants to make 80 puzzles. Find th

kari74 [83]

Since the base is 3 inches and the height is 4 inches, as well as the area of a triangle being base*height/2, we get 3*4/2=6 in. for each triangle. Since we need 20 pieces for each puzzle, we multiply 6 by 20 to get 120. In addition, since 80 puzzles are needed, with 20 pieces for each puzzle, we have 120 inches for each puzzle and 120*80 = 9600 square inches of wood used

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3 years ago

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Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

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3 years ago

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How would you solve this problem? ((2x^12y^3)/(x^10y))^-5

Hatshy [7]

There is no equals sign. Are we looking for x, or y?

Either way, with the -5 exponent outside the parentheses, you can multiply that to each exponent in the fraction to get rid of it.

I'm not sure what you mean by 2x^12y^3. Is it an exponent within another exponent?

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3 years ago

Find Lowest common factor of following questions . 56, 42, 28

Montano1993 [528]

Answer:

$\boxed{\textsf{ The LCM of 56 , 42 , 28 is \textbf{ 168}.}}$

Step-by-step explanation:

We need to find out the LCM of 56 , 42 , 28 . So Lowest Common Multiple known as LCM is the lowest multiple which is divisible by all the numbers whose LCM is taken out . It can we done by two methods. Both of which are discussed in the attachment .

For complete solution kindly refer to the attachment .

Related Information :- 

• HCF :-

It stands for Highest Common Factor . It is the highest numbers which divides out completely the numbers without leaving remainder of the numbers whose HCF is we are finding out .

3 0

3 years ago