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3 years ago

HELP ME PLEASE BRAINLIEST ANSWER PLEASE HELP ME

Mathematics

1 answer:

avanturin [10]3 years ago

8 0

Answer:

alright hers your brainliest and thank you very much i really appreciate it

Step-by-step explanation:

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5. Molly has 5 sticks of lengths 2,4,6,8, and 10 inches. Using three sticks at 1 point

sergeinik [125]

Answer:

4, 6 & 8 / 4, 8 & 10 , / 6, 8 & 10

So 3 triangles

Step-by-step explanation:

The longest side of a triangle has to be greater than the difference of the other 2 sides, and less than the sum of the other 2.

diff < long side < sum

Not equal to, less than & greater than.

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2 years ago

Solve the following equation. 2(x+2)−4x=8 Question 1 options: x=−2 x=3 x=−3 x=1

Tanya [424]

Step-by-step explanation:

2(x + 2) - 4x = 8

2x + 4 - 4x = 8

2x - 4x = 8 - 4

-2x = 4

x = 4/-2

x = -2

Option → A

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2 years ago

The formula for the area of a trapezoid is A = h(b1 + b2), where A = area, h = height, b1 = base 1, and b2 = base 2. For a trape

enyata [817]

The area of the trapezoid is A= 56

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3 years ago

Read 2 more answers

Complete the table.

Brilliant_brown [7]

Answer:

I believe the answer is 65%

Step-by-step explanation:

95/65%=61.75

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3 years ago

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

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3 years ago