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3 years ago

Hurry ASAP need help please !!!!!!

Mathematics

2 answers:

lara [203]3 years ago

8 0

Answer:

100y^4x^2

Step-by-step explanation:

^ means that's where an exponent is, so 100y exponent 4 x exponent 2.

sesenic [268]3 years ago

6 0

Answer:

100y^4×x² is your answer

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Identify the equation of the circle J with center K(-7,3) and radius 6.

andreyandreev [35.5K]

Answer:

equation of the circle J with center K(-7,3) and radius 6 is=

x^2+y^2+14x-6y+22=0

Step by step explanation:

Equation of circle with given centre (h,k) and radius r is

(x-h)^2+(y-k)^2=r^2

Given centre are K(-7,3) and radius 6.

So equation of Circle=

(x- -7)^2+(y-3)^2=6^2

x^2+14x+49+y^2-6y+9=36

x^2+y^2+14x-6y+22=0 answer

8 0

3 years ago

Read 2 more answers

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

Meredith picked 4 times as many green peppers as red peppers. If she picked a total of 20 peppers, how many green peppers did sh

Misha Larkins [42]

Let's have X represent the number of red peppers Meredith picked:

X = red peppers

We know that Meredith picked 4 times as many green peppers as red peppers, so based on this:

green peppers = 4*(red peppers) = 4X

In total, she picked 20, so:

Red peppers + Green peppers = 20
X + 4X = 20
5X = 20
X = 4

So, Meredith picked 4 red peppers and 16 (4 times 4) green peppers!

4 0

3 years ago

If f is the function defined by f (x) = (1/x-1)/(x-1), then lim f (x) is equivalent to what?

vichka [17]

The limit of the function as <u>x tends to 2</u> is 1

Given the function f(X) expressed as;

$f(x)=\frac{\frac{1}{x-1}}{x-1} \\$