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3 years ago

What is the equation of the following line?

Mathematics

1 answer:

icang [17]3 years ago

8 0

Answer:

E

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

slope = rise / run = 7 / 1 = 7

m = 7

y-intercept = 0

So:

y = 7x + 0

y = 7x

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2. A machine burns m gallons of oil each hour on weekends and ngallons each hour on weekdays. How many gallons of oil are burned

Lynna [10]

The question says the machine uses up m gallons of oil each hour on weekends.

This means that if the machine works for 24 hours each day, it implies that:

$\text{Total amount of oil used up in a day = 24}\times m=24m$

There are only two days on weekends i.e. Saturday and Sunday.

This means that if the amount of oil used in 1 day in the weekend is 24m, then we can say:

Saturday: oil used is 24m

Sunday: oil used is 24m

Total oil used during the weekend is:

$24m+24m=48m$

4 0

11 months ago

I'LL GIVE BRAINLIEST!!!!!!!!!!

Xelga [282]

Answer:B.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If you write 14 to the power of six in expanded form how many factors will there be

MariettaO [177]

One it is expanded i believe you should get 6

8 0

3 years ago

Read 2 more answers

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

Rewrite the expression so that it is not in fractional form? (5)/tanx+secx

arsen [322]

There is no other way to rewrite the expression from fractional form

5 0

3 years ago

What is the equation of the following line? ​

What is the equation of the following line?