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AVprozaik [17]
3 years ago
6

How would it affect your results if you used a beaker with residual water in it to measure out your standardized sodium hydroxid

e solution?
Chemistry
1 answer:
kifflom [539]3 years ago
4 0
Accepting that you're utilizing NaOH answer for its essential properties in corrosive/base science, I can expect that pH is of significance. When you have an institutionalized arrangement of say 1M (molar) focus NaOH arrangement and you put it into a dry burette to do a titration or something, you are expecting that the arrangement has a 1 mol of NaOH for each one liter of arrangement (molarity = mols/liters).
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Determine the mass of 5.20 moles of C6H12
Vera_Pavlovna [14]
Hello!
We have the following data:

m (mass) = ? 
n (number of moles) = 5.20 moles
MM (Molar mass of C6H12) 
C = 6*12 = 72 amu
H = 12*1 = 12 amu
--------------------------
MM (Molar mass of C6H12) = 72 + 12 = 84 g/mol

Now, let's find the mass, knowing that:

n =  \dfrac{m}{MM}

5.20\:\:\diagup\!\!\!\!\!\!\!mol =  \dfrac{m}{84\:g/\diagup\!\!\!\!\!\!\!mol}

m = 5.20*84

\boxed{\boxed{m = 436.8\:g}}\end{array}}\qquad\checkmark


6 0
3 years ago
What does the atomic number of each atom represent?
saw5 [17]
It's the number of Protons of that atom..
6 0
3 years ago
Molar mass of K2SO4 = 174.0 g/mol
Nastasia [14]
Not sure what you need to know, but if it’s true or false it would be false. it’s actually 174.26
8 0
3 years ago
Please answer
lutik1710 [3]

Answer:

See Explanation

Explanation:

8.  3, 1, -1, +1/2 => 3pₓ¹ => Aluminum

9.  4, 2, +1, +1/2 => 4d₁¹ => Chromium

10. 6, 1, 0, -1/2 => 6p₀² => Argon

11.  4, 3, +3, -1/2 => 4f₊₃² => Lutetium

12. 2, 1, +1, -1/2  => 2p₊₁² => Neon

8 0
3 years ago
Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?
LiRa [457]

Answer:

6.460 gm  is the correct answer .

Explanation:

Given

Kate’s blood volume=3.8L

blood glucose=170\  mg/dL

As we know that

1\ dL= 10^{-1}\ litre

The 10^{-1}   includes the blood glucose of the 170\  mg/dL,

So 3.8L. of the Kate’s blood volume  can be determined by

=\ \frac{170 * 3.8 }{10^{-1} }

=170 * 38 \ mg

=6460\ mg

To convert into the gm we have divided by the 1000

6.460 \ gm

Therefore the glucose in her blood=

6.460 \ gm

3 0
3 years ago
Read 2 more answers
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