Answer:
18.4 g
Explanation:
M(He) = 4.0 g/mol
4.6 mol * 4.0 g/ 1 mol = 18.4 g
Answer:
1) THE AGE OF THE SAMPLE 2) URANIUM- LEAD DATING
Explanation:
The answer to your question is 16grams
Answer:
See below in bold.
Explanation:
Nitrogen, Hydrogen and Oxygen are the elements present in ammonium nitrate.
The Molar Mass = 2N + 4H + 3 O
= 2*14.007 + 4*1.008 + 3*15.999
= 80.043.
Percentage of Nitrogen = (2 * 14.007) * 100 / 80.043
= 35.00 %.
Percentage of Hydrogen = (4* 1.008) * 100 / 80.043
= 5.04%.
Percentage of Oxygen = (3 * 15.999) * 100 / 80.043
= 59.96 %.
