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Ludmilka [50]
3 years ago
13

Please help see pic above

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Step-by-step explanation:

this is may help you this is my answer to your answer

You might be interested in
A square pyramid has a base length of 4 inches. The height of each triangular face is 12 inches. What is the surface area of the
Wittaler [7]

Answer:

The surface area of the given pyramid is 112 inches^{2}.

Step-by-step explanation:

Base length of the pyramid = 4 inches

Area of the base = length^{2}

                            = 4^{2}

                            = 16

Area of its base = 16 inches^{2}

Area of one of its triangular surface = \frac{1}{2} x base x height

                                 = \frac{1}{2} x 4 x 12

                                 = 2 x 12

                                 = 24 inches^{2}

Area of all its four triangular surfaces = 4 x 24

                                                       = 96 inches^{2}

surface area of the pyramid = sum of areas of all its surfaces

                                               = 16 + 96

                                       = 112 inches^{2}

The surface area of the given pyramid is 112 inches^{2}.

8 0
3 years ago
Wright the ratio 4.5 : 2.35 in the form n : 1
sergeinik [125]

Answer:

\frac{9}{47}: 1

Step-by-step explanation:

you can divide both sides by 2.35 to get the right side to be 1:

4.5: 2.35\\\frac{9}{47}: 1

6 0
3 years ago
0.38x < 25 -10.81 - 10
marusya05 [52]

Answer:

Inequality Form :

x < 11.02631578

Interval Notation :

( − ∞, 11.02631578)

4 0
3 years ago
Read 2 more answers
What is the volume of the prism?
Dmitry [639]
The volume would be 2040
7 0
3 years ago
Copy DEF to the line so that S is the vertex. This task will be complete when you have constructed an angle with vertex S that i
tino4ka555 [31]

Explanation:

There are numerous videos and web sites that can show you the process of copying an angle. Some are animated. The best we can do here is show you a diagram with instructions. Of course, your curriculum materials already provide that.

__

1. Set the compass to a convenient radius. Use that to draw an arc through rays ED and EF, using point E as the center.

2. Without changing the compass setting, draw a similar arc using S as the center, making sure it crosses the line containing S and extends far enough to accommodate the following steps. (In the attached, we show a full circle, because the tool we used won't draw an arc with a specific radius.)

3. Mark the points where the arc crosses ED as G, and where it crosses EF as H. Mark the point where the arc crosses the line containing S as I.

4. Set the compass radius to the distance GH. Using I as the center draw an arc with that radius so that it crosses the one made in step 2. Call that intersection point J. (Again, we have shown a circle because of the limitations of the tool being used for our diagram.)

5. Draw ray SJ to complete the angle copy.

4 0
3 years ago
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