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Andre45 [30]
3 years ago
8

Please help! I need it fast!

Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer:

fish dont drown nice try :/

zmey [24]3 years ago
4 0

Answer:

no fish drowned because the fishes fell on water

Step-by-step explanation:

You might be interested in
Maggie is creating a cushion for a circular stool. The stool has a diameter of 14 inches. If she needs fabric to extend 2 inches
Marianna [84]

Answer:

396 in.^2

Step-by-step explanation:

The cushion is shaped like a cylinder with 14 inch diameter and 2 inch height.

We need to find the surface area of the cylinder.

diameter = 14 in.

radius = diameter/2 = 7 in.

height = 2 in.

A = 2(pi)r^2 + 2(pi)rh

A = 2(3.14159)(7 in.)^2 + 2(3.14159)(7 in.)(2 in.)

A = 395.84 in.^2

A = 396 in.^2

8 0
2 years ago
7 2/15+52/3+9 13/15 a. 20 2/3 B.21 10/15 C.21 2/3 D.22 2/3 pls do i will mark brainlessness
Andreyy89

Answer:

101/3 or 33 2/3

Step-by-step explanation:

7 2/15=107/15

9 13/15=138/15

107/15+52/3+138/15

107/15+138/15+52/3

245/15+52/3

245/15+260/15

505/15

simplify,

101/3

8 0
2 years ago
What is the answer pls?
inna [77]

:) Hope this answers your question :)

6 0
3 years ago
Y - Circle
Kaylis [27]

Answer:

9cm

Step-by-step explanation:

making perpendicular "A" from center "O"

we get,OA=4cm(half of 8cm)

Now,

In triangle POA,

h^2=p^2+b^2

5^2=4^2+b^2

25=16+b^2

9=b^2

b=3cm

PA=3cm

hence,length of chords=3+3=9cm

6 0
2 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
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