The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
2
Step-by-step explanation:
You don't measure cereal in the others because feet, meters and millimeters are too big. Hope this helps.
Answer:
<h3>X = 3/5 </h3>
3/5x + 3 = 6
3/5x = 6 - 5
3/5x = 1
<h3><u>Multiplying </u><u>both </u><u>the </u><u>sides </u><u>with </u><u>5x </u></h3>
3/5x (5x) = 1* 5x
3 = 5x
3/5 = X
Answer:
Parallel: extending in the same direction, everywhere equidistant.
Perpendicular: ar an angle of 90 to a givin line, plane or surface.
