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2 years ago

I have 1,141 point i thought i might share them you here you go

Mathematics

1 answer:

zaharov [31]2 years ago

7 0

Answer:

Thank you, person.

I hope this is good enough:

you want to talk about anything

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A triangle has side lengths of 7.1, 12.6, and b. Which of the following CANNOT be b? (A) 5.7 (B) 7.5 (C) 10.1 (D) 18.5 (E) 19.9

GuDViN [60]

-- When the 7.1 and 12.6 sides both point in exactly the same direction,
their open ends are 5.5 apart. So the missing side must be greater than 5.5 .
All of the choices are greater than 5.5 , so we haven't found it yet.

-- When the 7.1 and 12.6 point in opposite directions, their open ends are
19.7 apart. So the missing side can't be greater than 19.7, otherwise the
two sides we know couldn't reach between its ends. <u>Choice 'E'</u> is greater
than 19.9, so it can't be the missing side.

8 0

2 years ago

I need help asap with this question it’s due tonight

Vilka [71]

Answer:

The answer is 44 cm^2

I hope it helps

3 0

3 years ago

Read 2 more answers

Write a multiplication equation that describes the picture of the half pants below use fraction below

Lady_Fox [76]

Can i see the picture

8 0

2 years ago

Please help me solve this problem

ss7ja [257]

Answer:

<h2>Number of solutions: 3</h2><h2>Type: -10, -2, 2.8</h2>

Step-by-step explanation:

f(x) = 0 - the solutions are the x-intercepts.

Look at the picture.

7 0

2 years ago

In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi

valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges

$=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\$

$=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329$

6 0

2 years ago