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snow_tiger [21]
3 years ago
13

Determine the unit rate of the following. 9 yards of material for 5 dresses The unit rate isyd / dress (Type a whole number or a

decimal.)​
Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer: (9/5) or 1.8 dresses/hr

Step-by-step explanation:

9 yards/5 dresses = (9/5) dresses/hr

(9/5) = 1 4/5 = 1.8 dresses/hr

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If you were 2 years old in 2011 how old would you be in 2020?
Roman55 [17]

Answer:

11 years

Step-by-step explanation:

2 years that you were in 2011

2020-2011= 9

2+9=11

also meaning they were born in 2009

2020-2009 also equals 11

this prolly doesnt make sense but hope it helps :) <3

4 0
3 years ago
Read 2 more answers
Solve for m. 13m−23=113
antoniya [11.8K]

Answer:

Exact form: 136/13

Decimal form: 10.46153846

Mixed number form: 10 6/13

8 0
3 years ago
ANSWER MY QUESTION PLEASE
mina [271]
When you plug the equation into a graphing calculator the x-intercept is -5
Or you can set the equation equal to 0 and solve for x.

6 0
3 years ago
Can some please answer this
Sonbull [250]

9514 1404 393

Answer:

  B  (2 violet)

Step-by-step explanation:

Let the colors be represented by their first letter. Then the balances give rise to two equation:

  o +y +b +v = r +g +b

  o +y +v = g +v

Subtracting the second equation from the first gives ...

  (o +y +b +v) -(o +y +v) = (r +g +b) -(g +v)

  b = r +b -v

Adding v-b to both sides, we have ...

  b +(v -b) = r +b -v +(v -b)

  v = r

Multiplying this result by 2, we can match the final balance:

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7 0
3 years ago
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Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

-\frac{1}{3\imath}+\frac{18\imath}{3\imath}

-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
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