Given Information:
Diameter of the cylindrical tub = d = 50 cm = 0.50 m
Acceleration = α = 3g
Required Information:
1. Rotation rate in rev/min = ω = ?
2. Tangential speed in m/s = v = ?
Answer:
1. ω = 103.5 rev/min
2. v = 2.71 m/s
Explanation:
We know that centripetal acceleration is given by
α = ω²r
Where ω is the angular speed or rotation rate and r is the radius.
The relation between diameter and radius is given by
r = D/2
r = 0.50/2
r = 0.25 m
Since it is given that the acceleration is equal to 3g where g is the gravitational acceleration 9.81 m/s².
α = ω²r
3g = ω²r
ω² = 3g/r
ω = √(3g/r)
ω = √(3*9.81/0.25)
ω = 10.84 rad/s
To convert rad/s into rev/s divide it by 2π
ω = 10.84/2π
ω = 1.752 rev/s
To convert rev/s into rev/min multiple it by 60
ω = 1.752*60
ω = 103.5 rev/min
Therefore, the rotation rate is 103.5 rev/min
2. The tangential speed can be found using
v = ωr
Where ω is the rotation rate in rad/s and r is the radius.
v = 10.84*0.25
v = 2.71 m/s
Therefore, the tangential speed is 2.71 m/s
Answer:
they better come prepared
Explanation:
they Gonna get coronavirus
To solve this problem it is necessary to apply the equations given from Bernoulli's principle, which describes the behavior of a liquid moving along a streamline. Mathematically this expression can be given as,
Where,
Pressure at each state
= Density
Velocity
Re-organizing the expression we can get that
Our values are given as
Normal Conditions
Replacing we have,
If we consider that there is a balance between the two states, the Force provided by gravity is equivalent to the Support Force, therefore
Here the lift force is the product between the pressure difference previously found by the effective area of the aircraft, while the Force of gravity represents the weight. There,
Equating,
Therefore the weight of the plane is 14535N
Answer: Mechanical advantage is the measure of the force amplification achieved by using a tool , mechanical device or machine . The machine preserve the input power and supply trade off force. against movement to obtain a desired amplification in the output force .
Explanation: hope this helps
speed of point A is given as
here r = distance from the axis
so here we have
now the distance of point A and B is 0.71 m
while the distance of axis from point A is 0.91 m
so distance of axis from point B will be given as
now for the speed of point b is given as
so end point B will move with speed 37.26 m/s