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3 years ago

9

Smooth muscle is found mainly in

1 answer:

Arlecino [84]3 years ago

8 0

Answer: the walls of hollow organs such has blood vessels, digestive tract organs, urinary bladder, and uterus.

Explanation:

You might be interested in

The mass number of an atom of carbon (C) represents the total number of protons in the atom. neutrons and electrons in the atom.

docker41 [41]

protons and neutrons in the atom.

Explanation:

The mass number of an atom of carbon represents the total number of protons and neutrons in the atom.

Mass number = number of protons + number of neutrons.

The mass of an atom is concentrated in the nucleus of the atom.
The particles in the nucleus are called nucleons are they are made up of the protons and neutrons.
Protons are positively charged.
Neutrons carry no charges.
Together, they make mass of atom.
The mass of electrons are negligible

Learn more;

Mass number brainly.com/question/2597088

#learnwithBrainly

3 0

3 years ago

A photograph of you and your friends at your 8th birthday party.is it secondary or primary source and why?

Reptile [31]

Answer:

primary source

Explanation:

the explanation is in the image above

brainliest please

7 0

3 years ago

A 282 kg bumper car moving 3.50 m/s collides with a 155 kg bumper car moving -1.38 m/s. Afterwards the 282 kg car moves at 1.10

icang [17]

Answer:

4.03 m/s

Explanation:

Initial momentum = final momentum

(282 kg) (3.50 m/s) + (155 kg) (-1.38 m/s) = (282 kg) (1.10 m/s) + (115 kg) v

v = 4.03 m/s

6 0

3 years ago

Read 2 more answers

The ball will oscillate along the z axis between z=dz=d and z=−dz=−d in simple harmonic motion. What will be the angular frequen

Eddi Din [679]

Answer:

$\omega = \sqrt{\dfrac{kq_0Q}{ma^3} }$

Explanation:

Additional information:

<em>The ball has charge </em> $-q_0$ <em>, and the ring has positive charge </em> $+Q$ <em> distributed uniformly along its circumference. </em>

The electric field at distance $z$ along the z-axis due to the charged ring is

$E_z= \dfrac{kQz}{(z^2+a^2)^{3/2}}.$

Therefore, the force on the ball with charge $-q_0$ is

$F=-q_oE_z$

$F=- \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}$

and according to Newton's second law

$F=ma=m\dfrac{d^2z}{dz^2}$

substituting $F$ we get:

$- \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}=m\dfrac{d^2z}{dz^2}$

rearranging we get:

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}=0$

Now we use the approximation that

$z^2+a^2\approx a^2$ <em>(we use this approximation instead of the original </em> $d^2+a^2\approx a^2$ <em> since </em> $z$ <em>, our assumption still holds )</em>

and get

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{(a^2)^{3/2}}=0$

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{a^{3}}=0$

Now the last equation looks like a Simple Harmonic Equation

$m\dfrac{d^2z}{dz^2}+kz=0$

where

$\omega=\sqrt{ \dfrac{k}{m} }$

is the frequency of oscillation. Applying this to our equation we get:

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Q}{a^{3}}z=0\\\\m=m\\\\k= \dfrac{kq_0Q}{a^{3}}$

$\boxed{\omega = \sqrt{\dfrac{kq_0Q}{ma^3} }}$

5 0

4 years ago

Can you plz make me brainliast?

bekas [8.4K]

Answer:

I dont know what to answer so im just gonna say ok

8 0

3 years ago