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ASHA 777 [7]
3 years ago
14

An obtuse triangle with area 12 has two sides of lengths 4 and 10. Find the length of the third side. (There are two answers.) (

Use law of cosines) ...?
Mathematics
1 answer:
mart [117]3 years ago
3 0
This question can be solved using the Herons equation where 
A = SQRT [s*(s-a)*(s-b)*(s-c)]

A = area of the triangle
a, b and c are the sides of the triangle

s = (a+b+c)/2

Since we are given the area, we can express "s" as a function of the third side c. This can be substituted in the original equation so as to obtain an expression to solve for the third side c

s = (4+10+c)/2 = (14+c)/2

using the solver function of the calculator or MS Excel, the third side is 7.21 units
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Jordan scored 19 points during a basketball game. She made a total of 9 baskets.
Over [174]

Answer:

B) 4 one-point baskets: 5 three-point baskets

Step-by-step explanation:

(4 x 1) + (5 x 3) = 19

4 0
3 years ago
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What is the square root of 28x to the third power y to the third power
Colt1911 [192]

Hello!

√28x³y³ is equal to 2xy\sqrt{7xy}

We can find this solution through the following steps.

  1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
  2. We then can rewrite 4 as 2² in our equation, leaving us with \sqrt{2^{2}*7*(x^{2}x)*y^{2}y }
  3. We will then move our x and 7, and rewrite 2^{2}*x^{2}* y^{2} as (2xy)^{2}
  4. We can then pull the terms from the radical leaving us with 2xy\sqrt{7xy}
6 0
4 years ago
The original price of an item was $20.00. It was marked up 25%. What is the new selling price?
Gre4nikov [31]

Answer:

$25

Step-by-step explanation:

Multiply $20 by 0.25 (which is 25% as a decimal)

$20 x 0.25 = $5

Add $5 to $20 which makes the answer $25

3 0
3 years ago
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what is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4, 6)
Korolek [52]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{We have}\ y+1=-3(x-5)\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The point-slope form:}\ y-y_1=m(x-x_1).\\\\\text{Put the value of slope and the coordinates of the point (4, 6) to the equation}:\\\\\boxed{y-6=\dfrac{1}{3}(x-4)}

8 0
3 years ago
Y = x^2+ 2x + 7<br> y = 7 + x
Lostsunrise [7]

Answer:

when x=0 y=7

when x=-1 y= 6

Step-by-step explanation:

to find x & y we can make the two x expressions equal to each other

x²+2x+7=7+x (we are going to set it equal to zero to find the roots/the x value)

x²+x=0

x(x+1)=0

x=0 x=-1 (two solutions for x)

now we just plug in these values and find the y values

when x=0 y=7

when x=-1 y= 6

5 0
4 years ago
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