Answer:
402 days.
Step-by-step explanation:
f(x)=1+1.5ln(x+1)
When f() = 10 we have:
10 = 1 + 1.5ln (x + 1)
ln (x + 1) = (10-1) / 1.5 = 6
x + 1 = e^6
x = e^6 - 1 = 402.4.
Draw a diagram to illustrate the problem as shown in the figure below.
The minimum depth of 2.5 m occurs at 12:00 am and at 12:30 pm.
Therefore the period i0s T= 12.5 hours.
The maximum depth of 5.5 m occurs at 6:15 am and at 6:45 pm. Therefore the period of T = 12.5 hours is confirmed.
The double amplitude is 5.5 - 2.5 = 3 m, therefore the amplitude is a = 1.5 m.
The mean depth is k = (2.5 + 5.5)/2 = 4.0 m
The model for tide depth is

That is,
d = -1.5 cos(0.5027t) + 4
where
d = depth, m
t = time, hours
A plot of the function confirms that the model is correct.
Dividing fractions is basically the same thing as multiplying but by the reciprocal. I will give an example.
1/2 divided by 1/3
To solve this you do 1/2 multiplied by 3/1 so you switch the numerator and denominator.
Answer:
The product of 2x + y and 5x – y + 3 is 10x^2+ 3xy + 6x - y^2 + 3y
Step-by-step explanation:
The product of the two expressions can be expressed mathematically as;
(2x +y) (5x -y +3)
To obtain the product of these expressions, we simply expand the brackets as follows;
2x(5x -y +3) + y(5x -y +3)
= 10x^2 - 2xy + 6x + 5xy - y^2 + 3y
= 10x^2- 2xy + 5xy + 6x - y^2 + 3y
= 10x^2+ 3xy + 6x - y^2 + 3y
The product of 2x + y and 5x – y + 3 is thus 10x^2+ 3xy + 6x - y^2 + 3y
<span>To minimize the perimeter you should always have a square.
sqrt(289) = 17
The dimensions should be 17 X 17
To see , try starting at length 1, and gradually increase the length.
The height decreases at a faster rate than the length increases, up until you reach a square.
Or if you want to use algebra, Say the width is 17-x
Then the length is 289/(17-x)
Now, this is bigger than 17+x, as shown here:
289/(17-x) > 17+x
289 > 289 - x^2
which is true.
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17
Again, the dimensions should be a square. 17 X 17.</span>