Question

Solve the quadratic equation: abx²- (a²-b²) x + (a-b) ² = 0​

Answer 1

Step-by-step explanation:

$ab {x}^{2} - ( {a}^{2} - {b}^{2} )x + (a - b) {}^{2} = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ ( {a}^{2} - {b}^{2} )± \sqrt{ {( {a}^{2} - {b}^{2} ) }^{2} - (4 \times ab \times {(a - b)}^{2} } }{2ab} \\ x = \frac{( {a}^{2} - {b}^{2} )±\sqrt{(a + b - 4ab} }{2ab {(a - b)}}$