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3 years ago

I NEED HELP BAD ALL WHO IN THE HELL KNOW HOW TO DO THIS

Chemistry

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

Explanation:

Argon has 22 neutrons and Boron has 6. The question asks how many more with means we are gonna subtract Boron neutrons for Argon neutrons. 22-6=16

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A 1 L container originally holds 0.4 mol of N2, 0.1 mol of O2, and 0.08 mole of NO. If the volume of the container holding the e

julsineya [31]

Answer:

a) $N_2=0.8mol/L$

b) $O_2=0.2mol/L$

c) $NO=0.16mol/L$

Explanation:

From the question we are told that:

Moles 0f Nitrogen $N_2=0.4$

Moles 0f Oxygen $O_2=0.1$

Volume Decrease $V_2=0.5L$

Generally, the equation for Concentration is mathematically given by

$C=\frac{moles}{V}$

For Nitrogen

$N_2=\frac{0.4}{0.5}$

$N_2=0.8mol/L$

For Oxygen

$O_2=\frac{0.1}{0.5}$

$O_2=0.2mol/L$

For Nitrogen

$NO=\frac{0.08}{0.5}$

$NO=0.16mol/L$

3 0

3 years ago

Need help !!!!! ASAP

Oksi-84 [34.3K]

<h2>Hello!</h2>

The answer is:

The approximate volume is 9.84 L.

$V=9.84L$

Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

$PV=nRT$

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant, which is equal to:

$R=0.082\frac{atm.L}{mol.K}$

So, we are given the information:

$n=1.5mol\\Temperature=300K\\Pressure=3.75atm$

Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:

$PV=nRT$

$V=\frac{nRT}{P}$

$3.75atm*V=1.5mol*0.082*\frac{atm.L}{mol.K}*300K$

$V=\frac{ 1.5mol*0.082*\frac{atm.L}{mol.K}*300K}{3.75atm}\\\\V=\frac{36.9atm.L}{3.75atm}=9.84L$

So, the approximate volume is 9.84 L.

$V=9.84L$

Have a nice day!

7 0

4 years ago