Answer:
(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ
(b) 4.898 MeV
Explanation:
In the nuclear reaction, it was stated that plutonium-242 decayed firstly to uranium-238 and alpha, and lastly to a stable uranium-238 by emitting a gamma ray. The balanced equation for the nuclear reactions is shown below:
(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ
(b) The energy emitted by releasing a gamma ray is calculated using:
E = hc/λ
where
h = 4.136*10^-15 eV.s
c = 299792458 m/s
λ = 0.02757 nm = 0.02757*10^-9 m
Therefore:
E = (4.136*10^-15)*(299792458)/0.02757*10^-9 = 44974.31 eV
The total energy if the stable 238U was produced directly would be
4.853*10^6 + 44974.31 = 4.898 MeV
Answer: B.) Salt and water
Explanation: A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.
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Answer:
In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation
Explanation:
Answer:
5.18 m x 0.77 m x 10.22 m3 = 40.763492 m^5
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