Answer:
Explanation:
Cu²⁺ + 2e⁻ → Cu ( copper gets reduced )
Cu → Cu²⁺ + 2e⁻ ( copper gets oxidized )
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Answer:
<u>36 times</u>
Explantaion:
The force exerted between two charged particles is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
In the case of S and q: The distance of separation is 1 unit
F(Sq) α S*q/1²
In the case of S and p: the distance is 6 units
F(Sp) α S*p/6²
therefore:
F(Sq) = 36 * F(Sp)
Answer: This image is the answer to this question.
Explanation:
Answer:
sorry!!!
Explanation:
its to small I can't see it
(H2O) which means 2 hydrogen atoms and 1 oxygen
