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Tems11 [23]
3 years ago
9

A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.1

50 m3 of air at a pressure of 3.40 atm .
The piston is slowly pulled out until the volume of the gas is increased to 0.430 . If the temperature remains constant, what is the final value of the pressure?
Physics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer:

it could be 69

Explanation:

because it is a solution

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<span>If the entropy is greater than the enthalpy, it will have more spontinaity</span>
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Collins body metabolizes caffeine at a rate of 14.3% per hour (so the amount of caffeine in Collins body decreases by 14.3% each
Oksanka [162]

Answer:

It will take 4.5 h to metabolize 50% of the ingested caffeine.

Explanation:

Hi there!

We have to find how long will it take Collin´s body to metabolize 50% (40 g) of the ingested caffeine. We know that Collin´s body metabolizes 14.3 % of the amount of caffeine each hour. Then, every hour the caffeine will be reduced by 14.3 %.

After the first hour, the amount of caffeine will be:

80 - 80 · 0.143 = 68.56

Expressed in other form

80 · (1 - 0.143) = 68.56

80 · 0.857 = 68.56

After the second hour, the amount of caffeine will be:

68.56 - 68.56 · 0.143 = 58.75592

or

68.56 · 0.857 =  58.75592

Since 68.56 = 80 · 0.857, we could write the amount of caffeine after 2 hours as:

80. 0.857 · 0.857  =  58.75592

After the third hour:

58.75592 - 58.75592 · 0.143 = 50.35382344

or

58.75592 · 0.857 = 50.35382344

In the same way, since 58.75592 = 80. 0.857 · 0.857  the amount of caffeine after 3 hours will be:

80. 0.857 · 0.857  · 0.857 = 50.35382344

Then after x hours, the amount of caffeine in the body will be:

80 mg · 0.857ˣ

We have to find the value of x for which that expression is equal to 40 mg:

80 mg · 0.857ˣ = 40 mg

0.857ˣ = 40 mg/ 80 mg

0.857ˣ = 0.5

Apply ln to both side of the equation:

ln(0.857ˣ) = ln(0.5)

Apply logarithm property : ln(xᵃ) = a ln(x)

x ln(0.857) = ln(0.5)

x = ln(0.5)/ln(0.857)

x = 4.5 h

It will take 4.5 h to metabolize 50% of the ingested caffeine.

3 0
3 years ago
A 20-foot ladder is leaning against the wall. If the base of the ladder is sliding away from the wall at the rate of 3 feet per
tamaranim1 [39]

Answer:

<u>6.87 ft/s</u> is the rate at which the top of ladder slides down.

Explanation:

Given:

Length of the ladder is, L=20\ ft

Let the top of ladder be at height of 'h' and the bottom of the ladder be at a distance of 'b' from the wall.

Now, from triangle ABC,

AB² + BC² = AC²

h^2+b^2=L^2\\h^2+b^2=20^2\\h^2+b^2=400----1

Differentiating the above equation with respect to time, 't'. This gives,

\frac{d}{dt}(h^2+b^2)=\frac{d}{dt}(400)\\\\\frac{d}{dt}(h^2)+\frac{d}{dt}(b^2)=0\\\\2h\frac{dh}{dt}+2b\frac{db}{dt}=0\\\\h\frac{dh}{dt}+b\frac{db}{dt}=0--------2

In the above equation the term \frac{dh}{dt} is the rate at which top of ladder slides down and \frac{db}{dt} is the rate at which bottom of ladder slides away.

Now, as per question, h=8\ ft, \frac{db}{dt}=3\ ft/s

Plug in h=8 in equation (1) and solve for b. This gives,

8^2+b^2=400\\64+b^2=400\\b^2=400-64\\b^2=336\\b=\sqrt{336}=18.33\ ft

Now, plug in all the given values in equation (2) and solve for \frac{dh}{dt}

8\times \frac{dh}{dt}+18.33\times 3=0\\8\times \frac{dh}{dt}+54.99=0\\8\times \frac{dh}{dt}=-54.99\\ \frac{dh}{dt}=-\frac{54.99}{8}=-6.87\ ft/s

Therefore, the rate at which the top of ladder slide down is 6.87 ft/s. The negative sign implies that the height is reducing with time which is true because it is sliding down.

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