Explanation:
Given that,
Length of gold wire, l = 4 m
Voltage of battery, V = 1.5 V
Current, I = 4 mA
The resistivity of gold, ![\rho=2.44\times 10^{-8}\ \Omega-m](https://tex.z-dn.net/?f=%5Crho%3D2.44%5Ctimes%2010%5E%7B-8%7D%5C%20%5COmega-m)
Resistance in terms of resistivity is given by :
![R=\dfrac{\rho l}{A}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7B%5Crho%20l%7D%7BA%7D)
Also, V = IR
So,
![\dfrac{V}{I}=\dfrac{\rho l}{A}](https://tex.z-dn.net/?f=%5Cdfrac%7BV%7D%7BI%7D%3D%5Cdfrac%7B%5Crho%20l%7D%7BA%7D)
A is area of wire,
, r is radius, r = d/2 (diameter=d)
![\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m](https://tex.z-dn.net/?f=%5Cdfrac%7BV%7D%7BI%7D%3D%5Cdfrac%7B%5Crho%20l%7D%7B%5Cpi%20%28d%2F2%29%5E2%7D%5C%5C%5C%5C%5Cdfrac%7BV%7D%7BI%7D%3D%5Cdfrac%7B4%5Crho%20l%7D%7B%5Cpi%20d%5E2%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B%5Cdfrac%7B4%5Crho%20l%20I%7D%7BV%5Cpi%7D%7D%20%5C%5C%5C%5Cd%3D%5Csqrt%7B%5Cdfrac%7B4%5Ctimes%202.44%5Ctimes%2010%5E%7B-8%7D%5Ctimes%204%5Ctimes%204%5Ctimes%2010%5E%7B-3%7D%7D%7B1.5%5Ctimes%20%5Cpi%7D%7D%20%5C%5C%5C%5Cd%3D18.2%5C%20%5Cmu%20m)
Out of four option, near option is (C) 17 μm.
Answer:
In the electric field, the like charges repel each other, and the unlike charges attract each other, whereas in a magnetic field the like poles repel each other and the unlike poles attract each other.
Explanation:
Answer:
(a) 40.6 degree
Explanation:
When refraction takes place from slab to water, the critical angle is 60 degree.
Use Snell's law
refractive index of water with respect to slab
![\mu _{w}^{s}=\frac{Sin60}{Sin90}](https://tex.z-dn.net/?f=%5Cmu%20_%7Bw%7D%5E%7Bs%7D%3D%5Cfrac%7BSin60%7D%7BSin90%7D)
![\frac{\mu _{w}}{\mu _{s}}=0.866](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20_%7Bw%7D%7D%7B%5Cmu%20_%7Bs%7D%7D%3D0.866)
![\frac{1.33}{\mu _{s}}=0.866](https://tex.z-dn.net/?f=%5Cfrac%7B1.33%7D%7B%5Cmu%20_%7Bs%7D%7D%3D0.866)
μs = 1.536
Now for slab air interface, the critical angle is C.
![\mu _{a}^{s}=\frac{SinC}{Sin90}](https://tex.z-dn.net/?f=%5Cmu%20_%7Ba%7D%5E%7Bs%7D%3D%5Cfrac%7BSinC%7D%7BSin90%7D)
![\frac{\mu _{a}}{\mu _{s}}=\frac{SinC}{Sin90}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20_%7Ba%7D%7D%7B%5Cmu%20_%7Bs%7D%7D%3D%5Cfrac%7BSinC%7D%7BSin90%7D)
1 / 1.536 = Sin C
C = 40.6 degree
Answer:Some of the heavier elements in the periodic table are created when pairs of neutron stars collide cataclysmically and explode
Explanation: