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nekit [7.7K]
3 years ago
9

A particular grocery bag can withstand 40 N of tension force before it rips. If a shopper places 3 kg of food in the bag, what i

s the maximum acceleration the bag can withstand before ripping?
Physics
2 answers:
snow_lady [41]3 years ago
8 0

Answer;

    = 13.33 m/s²

Solution;

From the second Newton's law of motion;

F= ma

F is the force = 40 N

M is the mass = 3 kg

a is the acceleration;

40 = 3 × a

a = 40/3

    = 13.33 m/s²

Hence; the maximum acceleration the bag can withstand before ripping is 13.33 m/s²

Lesechka [4]3 years ago
3 0

Answer:

3.3 is right

Explanation:

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What are three disadvantages of making and using plastic? It pollutes the land and water. It requires cutting down trees for raw
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You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
Citrus2011 [14]

Answer:

\triangle x=3.2*10^-^5 m

Explanation:

From the question we are told that

Height of circular cylinder is h= 1.8m

Diameter of cylinderD=4cm=>0.04m

Horizontal Force  F=900N

Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\

Generally the formula for shear modulus is mathematically represented by

G=\frac{\tau}{\gamma}

Where

G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain

G=\frac{F/A}{\triangle x/L}

G=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}

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