Speed = Distance ÷ Time
Speed = 116 ÷ 29
Speed = 4
Answer:
774.8 secs
Explanation:
distance(d)= speed(v)* time(t)
calculate speed:
refractive index = speed of light (c)/ speed of light in medium (v)
1.56 = 3*10^8*v
v=192307692.3 m/s
d = v *t
t = d/v
on substituting values:
t = 774.8 secs
Answer:
The wavelength of sunlight that can cause this bond breakage is 242 nm
Explanation:
The minimum energy of the sunlight that'll break Oxygen-oxygen bond must match 495 KJ/mol
But 1 mole of any molecule contains 6.02 × 10²³ molecules/mol
Each molecule of Oxygen will require (495 × 10³)/(6.02 × 10²³) = 8.22 × 10⁻¹⁹ J
E = hf
v = fλ
f = v/λ
f = frequency of the sunlight
λ = wavelength of the sunlight
v = speed of light = 3.0 × 10⁸ m/s
E = hv/λ
λ = hv/E
h = Planck's constant = 6.63 × 10⁻³⁴ J.s
λ = (6.63 × 10⁻³⁴)(3 × 10⁸)/(8.22 × 10⁻¹⁹)
λ = 2.42 × 10⁻⁷ m = 242 nm.
Answer:
Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?
Using Coulomb's law:
F = 1/(4πE) x Q1 x Q2/ r^2
Where
k= 1/(4πE) = 9 x 10^9Nm2/C2
Therefore,
F = 9x 10^9 x 2.50 x 10^-5 x2.50 x
10^-5/. ( 0.5)^2
F= 5.625/ 0.25
F= 22.5N approximately
F= 23N.
To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.
Hence To = 23N, attractive. C ans.
Thanks.