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solniwko [45]
3 years ago
14

Ms. Mary Mack walked around her block from her house for 200 meters. She arrived back at her house in 15 minutes. What was her d

isplacement?
200 meters
0
13.3 meters/minute
Physics
1 answer:
inysia [295]3 years ago
5 0

Answer:

d = 0 [m]

Explanation:

Displacement is understood as the length and direction that a body travels to move from an initial point to an endpoint.

This displacement is represented with a vector or straight line that indicates the distance of the displacement and its length.

This displacement in an easier way to understand. It is the distance between the start point and the endpoint of the journey. Since the second point is equal to the first point, since Mary returns to the same place, there is no difference between the displacement.

Therefore the displacement is zero.

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What happened to the balloon when it was placed on the bottle with the baking soda and vinegar and why.
user100 [1]

Answer:

The ballon would be inflated. The reason is that the sodium bicarbonate in baking soda reacts with acetic acid in vinegar to produce gas.

Explanation:

The main component of baking soda is sodium bicarbonate, {\rm Na_{2}CO_{3}}.

Vinegar is mostly a solution of acetic acid {\rm CH_{3}COOH} in water.

Acids such as acetic acid react with carbonate salts. One of the products of such reactions is carbon dioxide {\rm CO_{2}}, a gas.

In this question, when the acetic acid in vinegar reacts with sodium bicarbonate in the baking soda, the following reaction would occur:

\begin{aligned}& {\rm Na_{2}CO_{3}}\, (aq) + 2\, {\rm CH_{3}COOH}\, (aq) \\ &\to 2\, {\rm CH_{3}COONa}\, (aq) + {\rm CO_{2}}\, (g)\end{aligned}.

The {\rm CO_{2}} produced would then inflate the ballon placed on the opening of the bottle.

5 0
2 years ago
4. A car, initially traveling east with a speed of
PilotLPTM [1.2K]

Answer:

150 m

Explanation:

Given,

u=5m/s

a=2m/s2

t=10s

v=?

s=?

Now,

v=u+at

=5+2×10

=5+20

=25m/s

So,

s=u+v/2×t

=5+25/2×10

=30/2×10

=15×10

=150m

5 0
3 years ago
A train slows from 60m/s to 20m/s in 50s
Dovator [93]

Answer:

a = -4/5 m/s^2

Explanation:

Acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

a = (20 m/s - 60 m/s) / 50 s

a = -40 m/s / 50 s

a = -4/5 m/s^2

hope this helps! <3

7 0
1 year ago
Read 2 more answers
Which contains the particles that are vibrating fastest?
Phantasy [73]

Answer:

Boiling water

Explanation:

3 0
2 years ago
A solid conducting sphere of radius 2 cm has a charge of 8microCoulomb. A conducting spherical shell of inner radius 4 cm andout
nika2105 [10]

Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

  • If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
  • So, we can write the following equation:

       E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)

  • As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
  • So, the +8 μC charge of  the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
  • So, on the outer surface of the shell there must be a charge that be the difference between them:

        Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C

  • Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

      E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C

  • As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
6 0
3 years ago
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