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artcher [175]
3 years ago
10

The manager at a supermarket arranged 10 rows of cans. He put 2 cans in the first row, 4 cans in the second row, and 6 cans in t

he third row. The manager continued to add 2 cans to each new row.
a. How many cans did the manager put in the fifth row? Show or explain how you got your answer.
b. What is the total number of cans the manager arranged in all 10 of the rows? Show or explain how you got your answer.
c. Describe the relationship between the row number and the number of cans in the row.
Mathematics
1 answer:
Elena-2011 [213]3 years ago
6 0
A)

2, 4, 6, 8, *10

The fifth row contains 10 cans.

----------------------------------------------------

b)

2+4+6+8+10+12+14+16+18+20=110

-----------------------------------------------------

c)
 
2*Row=Number Of Cans

When Row=1, Number Of Cans=2.

When Row=5, Number Of Cans=10.

When Row=10, Number Of Cans=20.
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aleksley [76]

it is clearly impossible

8 0
3 years ago
A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
2 Points
Mashcka [7]

Answer:

C. It would be shifted up.

Step-by-step explanation:

We base it off the y-intercept. Since -7 is <em>less</em><em> </em><em>than</em><em> </em>1, and our new function has a positive y-intercept, it would indeed be shifted up.

I am joyous to assist you anytime.

5 0
3 years ago
What is the value of this expression? 2.4 27.316
Rom4ik [11]

Answer:

If it is 2.4 times 27.316, it is 65.5584

Step-by-step explanation:

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2 years ago
Write the Riemann sum to find the area under the graph of the function f(x) = x^2 from x = 1 to x = 5.
makkiz [27]
I think the first one or the thrid one 
hope this help
6 0
3 years ago
Read 2 more answers
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