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Zepler [3.9K]
3 years ago
10

Help im really struggling here I would really appreciate it

Mathematics
1 answer:
sweet [91]3 years ago
8 0
The answer is B, 90 degrees counterclockwise rotation about the origin I hope this helps you out
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Use Pythagorean theorem
kogti [31]

Answer:

15

Step-by-step explanation:

a^2+b^2=c^2

y^2+8^2=17^2

Step 1: Simplify both sides of the equation.

y^2+64=289

Step 2: Subtract 64 from both sides.

y^2+64−64=289−64

y^2=225

Step 3: Take square root.  

y=15  

4 0
3 years ago
I need help with math
tatuchka [14]
Tell me the problems and i may be able to help

5 0
3 years ago
How are the numbers 3, 4, and 17 alike
Tanzania [10]
They are all prime numbers
4 0
2 years ago
Triangle Proofs Please help
oksian1 [2.3K]

Explanation:

There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.

<u>Statement</u> . . . . <u>Reason</u>

2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle

3. AD ≅ BD

and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle

4. ∠CAE = ∠CAD +∠DAE

and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate

5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality

6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality

7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality

8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate

9. ∠ACD ≅ ∠BCD . . . . CPCTC

10. DC bisects ∠ACB . . . . definition of angle bisector

4 0
2 years ago
what is the slope intercept form of the equation of the line described by (-4,-5), parallel to y=-2x -5
Eddi Din [679]

Answer:

y = - 2x - 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 5 ← is in slope- intercept form

with m = - 2, thus

y = - 2x + c ← is the partial equation of the line

To find c substitute (- 4, - 5) into the partial equation

- 5 = 8 + c ⇒ c = - 5 - 8 = - 13

y = - 2x - 13 ← equation of line

7 0
2 years ago
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