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Reil [10]
3 years ago
11

A floor is tiled with a pattern consisting of regular octagons and squares as shown. Find the measure of each angle at the circl

ed vertex. Then find the sum of the angles.
a. 135°, 90°, 1350, 360°
b. 90°, 90°, 90°. 270°
c. 135º. 135, 1359, 4050
d. 1200,120, 120°, 360°​
Mathematics
1 answer:
Alika [10]3 years ago
5 0

Answer:it would be A

Step-by-step explanation:because theres a 90 degree angle

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A square is inscribed in a circle of diameter 12 millimeters. What is the area of the shaded region? A square is inscribed in a
bezimeni [28]

Answer:  A. (72π - 144) mm²

<u>Step-by-step explanation:</u>

A_{shaded}=A_{circle}-A_{square}\\\\\\A_{circle}=\pi \cdot r^2\\.\qquad \ =\pi \bigg(\dfrac{12\sqrt2}{2}\bigg)^2\\\\.\qquad \ =\pi (6\sqrt2)^2\\.\qquad \ =72\pi\\\\\\A_{square}=side^2\\.\qquad \quad =\dfrac{12\sqrt2}{\sqrt2}^2\\\\.\qquad \quad =12^2\\\\.\qquad \quad =144\\\\\\\large\boxed{A_{shaded}=72\pi-144}

7 0
3 years ago
Express 3 objects as a percentage of 1 dozen<br>show working.​
user100 [1]

Answer:

25%

Step-by-step explanation:

1 dozen = 12

3 out of 12

3/12

Simplify

1/4

Multiply top and bottom by 25 to get a denominator of 100

25/100

25%

3 0
3 years ago
PLZ ANSWER QUICK IT WILL HELP A LOT!
OlgaM077 [116]

Answer: A

Step-by-step explanation: all answer choices have the negative sign for the x-value

4 0
3 years ago
Read 2 more answers
(13a² − 6a⁵ − 2a) − (−10a² − 11a⁵ + 9a)
Delicious77 [7]

Answer:

a x (23a+5a^4 - 11)

Step-by-step explanation:

(a x (13a - 6a^4 - 2) + 10a^2 + 11a^5 - 9a

rewite the expression and remove any unnecessary parentheses.

a x (13a - 6a^4 -2) + 10a^2 +11a^5 - 9a

factor the expression.

a x (23a - 6a^4-2+11a^4-9)

connect like terms.

your welcome

8 0
3 years ago
Water flows into a tank according to the rate F(t) = t+6/1+t, and at the same time empties out at the rate E(t) = ln(t+2)/t+1, w
Bas_tet [7]

Answer:

12.29minutes

Step-by-step explanation:

The net flow rate = flow in - flow out = F(t) - E(t) = t+6/1+t -  ln(t+2)/t+1 = [(t + 6) - ln(t+2)]/(t+1)

So, the amount of water present in the tank at time, t is A = net flow rate × time = [(t + 6) - ln(t+2)]/(t+1) × t = t[(t + 6) - ln(t+2)]/(t+1)

At t = 10 minutes,

A = t[(t + 6) - ln(t+2)]/(t+1)

A = 10[(10 + 6) - ln(10+2)]/(10+1)

A = 10[16 - ln12]/11

A = 10[16 - 2.485]/11

A = 10[13.515]/11

A = 135.15/11

A = 12.29 minutes

7 0
3 years ago
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