Eukaryotic cells contain membrane-bound organelles, such as the nucleus, while prokaryotic cells do not. Differences in cellular structure of prokaryotes and eukaryotes include the presence of mitochondria and chloroplasts, the cell wall, and the structure of chromosomal DNA.
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Answer and Explanation:
Due to <u>technical problems</u>, you will find the complete answer and explanation in the attached files
Answer:
The definition is listed in the clarification segment below, and according to the present circumstances.
Explanation:
It undergoes different morphological as well as biochemical modifications mostly during germination. Product contains nutrients and even some hydrolases such as energy, carbohydrates. Owing to the availability of phytic compounds, the seed coat seems to be very durable in nature. Hydrolytic enzymes launch their function by consuming oxygen throughout order to remove this hard coating. In several other processes, including the electron transport system as well as the Kreb process, oxygen also becomes necessary.
- The initial phase of germinating seeds requires anaerobic environments where even the enzymes dehydrogenase can function. The subsequent dehydrogenase enzyme brings the electron throughout the electron transport system from either the base to oxygen.
- Unless the oxygen frequency is compared with varieties A and B, it can be seen through the analysis that variety B actually absorbed more oxygen. Oxygen intake rates are also depending upon period.
- The impact of temperature mostly on absorption of oxygen seems to be present. Shift the supply at low temperatures have a low intake of oxygen, while varieties grown over extreme temperatures use much more oxygen. The metabolism of such a seedling is influenced by temperature. Metabolically active young plants display a larger intake of oxygen.
Black moths were more fit to survive to the environement, since many animals couldnt see them.
Answer:
The answer to your question is V2 = 0.92 l
Explanation:
Data
Volume 1 = V1 = 2.4 l
Pressure 1 = P1 = 1.5 atm
Temperature 1 = T1 = 273 °C
Volume 2 = V2 = ?
Pressure 2 = 4.5 atm
Temperature 2 = 313 °K
Process
To solve this problem use the Combined gas law
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (1.5 x 2.4 x 313) / (273 x 4.5)
-Simplification
V2 = 1126.8 / 1228.5
-Result
V2 = 0.92 l
