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julsineya [31]
3 years ago
12

Graph the function y = 2x3 – x2 – 4x + 5. To the nearest tenth, over which interval is the function decreasing?

Mathematics
2 answers:
daser333 [38]3 years ago
4 0
As you progress in math, it will become increasingly important that you know how to express exponentiation properly.

y = 2x3 – x2 – 4x + 5  should be written    <span>y = 2^x3 – x^2 – 4^x + 5.  The 
" ^ " symbol denotes exponentiation.

I see you're apparently in middle school.  Is that so?  If so, are you taking calculus already?  If so, nice!

Case 1:  You do not yet know calculus and have not differentiated or found critical values.  Sketch the function          </span>y = 2x^3 – x^2 – 4^x + 5, including the y-intercept at (0,5).  Can you identify the intervals on which the graph appears to be increasing and those on which it appears to be decreasing?

Case 2:  You do know differentiation, critical values and the first derivative test.  Differentiate  y = 2x^3 – x^2 – 4^x + 5 and set the derivative = to 0:

dy/dx = 6x^2 - 2x - 4 = 0.  Reduce this by dividing all terms by 2:

dy/dx = 3x^2 - x - 2 = 0    I used synthetic div. to determine that one root is x = 2/3.  Try it yourself.  This leaves the coefficients of the other factor, (3x+3); this other factor is x = 3/(-3) = -1.  Again, you should check this.

Now we have 2 roots:  -1 and 2/3

Draw a number line.  Locate the origin (0,0).  Plot the points (-1, 0) and (2/3, 0).  This subdivides the number line into 3 subintervals:

(-infinity, -1), (-1, 2/3) and (2/3, infinity).

Choose a test number from each interval and subst. it for x in the derivative formula above.  If the derivative comes out +, the function is increasing on that interval; if -, the function is decreasing.

Ask all the questions you want, if this explanation is not sufficiently clear.

lora16 [44]3 years ago
3 0

Answer:

Option 3 - (-0.7,1)  

Step-by-step explanation:

Given : Function  y=2x^3-x^2-4x+5

To find : Over which interval is the function decreasing?

Solution :

First we plot the graph using graphing calculator.

Refer the attached figure below.

Now, Examining the graph

From -\infty to (-0.667,6.63) the graph is increasing as the curve is increasing.

From (-0.667,6.63) to (1,2) the graph decreasing as the curve is decreasing.

From  (1,2) to \infty the graph is increasing as the curve is increasing.

So, The interval in which the function is decreasing is given by (-0.667,1)

Round to nearest tenth,  (-0.7,1)

Therefore, Option 3 is correct.

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Solve each equation separately:

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JulsSmile [24]

Answer: Option C.

Step-by-step explanation:

We have functions of r(θ)

In our graph, we can see that the minimum value of r is when θ = 0°, and the maximum value is when θ = 180°.

We also know that the graph is in the square (-5, 5)x(-5, 5) and you can see that the maximum radius is almost less than 5.

Then let's analyze the options:

A) r = 3 - 2*cos(θ)

the maximum is at the right angle, but the maximum is:

r = 3 -2*(-1) = 5, so this maximum value is bigger than the one in the graph.

B) r = 3 - sin(θ)

For the sin functions, the maximum and minimum do not correspond with the values i write earlier, so we can discard this option.

C) r = 3 - cos(θ)

The maximum is: r = 3 - (-1) = 4, so this may be the correct answer.

the minimum is r = 3 - 1 = 2,

this is a possible equation for our circle.

D) r = 2 - 2*cos(θ)

Here, when θ = 0, we have: r = 2 - 2*1 = 0, but in the graph we can see that the radius is not 0 when θ = 0, so we can discard this option.

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