The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.
<h3>What is the molarity of 5% NaOH?</h3>
The molarity of 5% NaOH is 1.32 M
25 cc of NaOH neutralized 30cc of H₂SO₄ solution.
Equation of reaction is given below:
- 2 NaOH + H₂SO₄ ---> Na₂SO₄ + 2 H₂O
Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M
- Normality = Molarity × moles of H⁺ ions per mole of acid
moles of H⁺ ions per mole of H₂SO₄ = 2
Normality of H₂SO₄ = 0.55 x 2 = 1.1 N
In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.
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you can use the formula F=MA to find any mass of almost anything .
Answer:
An opinion is a statement describing a personal belief or thought that cannot be tested (or has not been tested) and is unsupported by evidence. ... Theories are not described as true or right, but as the best-supported explanation of the world based on evidence.
It depends on weather or not the chemicals used can cause problems if not and it's a safe substance than yes they should pour it down the drain
Answer:
The mass of (NH₄)₂S we may add to the solution is: 1.98 g
Explanation:
We interpret the given data:
0.114 m → moles of solute in 1kg of solvent
255 g → the mass of solvent
As we have 0.114 moles of solute ((NH₄)₂S) in 1kg, we must determine the moles in our mass of solvent (255 g H₂O)
We convert the mass of solvent to kg → 255 g . 1 kg/1000g = 0.255 kg
Now we can determine the moles of solute, we used:
0.114 mol/kg . 0.255 kg = 0.02907 moles
If we convert the moles to mass → 0.02907 mol . 68.1g /1mol = 1.98 g
