Question

Write the empirical formula for given elements

Answer 1

Answer:

$Fe(CN)_{2}\\Fe(C_{2}H_{3}O_{2})_{2}\\\\Fe(CN)_{3}\\\\Fe(C_{2}H_{3}O_{2})_{3}$

Explanation:

$Fe^{2+}(CN^{-})_{2}--->Fe(CN)_{2}\\Fe^{2+}(C_{2}H_{3}O_{2}^{-})_{2}--->Fe(C_{2}H_{3}O_{2})_{2}\\\\Fe^{3+}(CN^{-})_{3}--->Fe(CN)_{3}\\\\Fe^{3+}(C_{2}H_{3}O_{2}^{-})_{3}--->Fe(C_{2}H_{3}O_{2})_{3}$