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Stels [109]
2 years ago
11

Write the empirical formula for given elements

Chemistry
1 answer:
rusak2 [61]2 years ago
3 0

Answer:

Fe(CN)_{2}\\Fe(C_{2}H_{3}O_{2})_{2}\\\\Fe(CN)_{3}\\\\Fe(C_{2}H_{3}O_{2})_{3}

Explanation:

Fe^{2+}(CN^{-})_{2}--->Fe(CN)_{2}\\Fe^{2+}(C_{2}H_{3}O_{2}^{-})_{2}--->Fe(C_{2}H_{3}O_{2})_{2}\\\\Fe^{3+}(CN^{-})_{3}--->Fe(CN)_{3}\\\\Fe^{3+}(C_{2}H_{3}O_{2}^{-})_{3}--->Fe(C_{2}H_{3}O_{2})_{3}

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How many moles of liquid water must freeze to remove 100 kJ of heat? (ΔHf = –334 J/<br> g.
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First figure out how many grams must freeze and then convert the grams to moles. 
<span>Hf = -334 J/g. Convert this to KJ/g by dividing by 1000. (There are 1000 Joules in a kJ). </span>
<span>Hf = -334 J/g ÷ 1000 J/kj = -0.334 kJ/g </span>
<span>Now, divide 100 kJ by -0.334 kJ/g (see how the units are lining up?) </span>
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When a bimetallic bar made of copper and iron strips is heated, the bar bends toward the iron strip. the reason for this is?
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2 years ago
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

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2 years ago
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