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sergij07 [2.7K]
3 years ago
5

What is the best name for the molecule below? a compound with 10 total carbons with a double bond and the rest single bonds. the

re is a straight chain of seven carbons along the bottom with a double bond between the third and fourth carbons when counting from left to right. there is a propyl group branching off of the fifth carbon from the left. 5-propyl-3-heptene 5-ethyl-3-octene 3-ethyl-5-octene 3-ethyl-4-heptene?
Chemistry
2 answers:
yanalaym [24]3 years ago
6 0
The correct answer is <span>5-propyl-3-heptene. </span>
Alina [70]3 years ago
5 0

Answer:

5-propyl-3-heptene

Explanation:

There is a straight chain of seven carbons along the bottom with a double bond between the third and fourth carbons when counting from left to right.

1  2   3  4  5  6  7

C-C-C=C-C-C-C

There is a propyl group branching off of the fifth carbon from the left.

1  2   3  4  5  6  7

C-C-C=C-C-C-C

                 |

                 C₃H₇

Th final structure is:

1        2      3    4     5      6       7

H₃C-CH₂-CH=CH-CH₂-CH₂-CH  ₃

                              |

                              C₃H₇

The  best name for the molecule is:

5-propyl-3-heptene

The side chain propyl is at the 5th C atom. Also the third bond from the left is a double bond. A seven C main chain is called heptane if there is no double bond. Since there is one double bond in the main chain it is named heptene.

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4 0
3 years ago
Consider the reaction 2 SO2(g) + O2(g) &lt;=&gt; 2 SO3(g), which is exothermic as written. What would be the effect on the equil
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Answer:

Removing O₂, means removing one of the reactants and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.

Explanation:

The principle that explains how changes in temperature, Concentration and Pressure of reactants or products of a reaction at equilibrium affect the equilibrium position of the reaction is the Le Chatelier's principle.

The Principle explains that a system/process if a system/process which is at equilibrium is disturbed/perturbed/constrained by one or more changes (in concentration, pressure or temperature), the system would shift the equilibrium position to counteract the effects of this change.

Removing O₂, means removing one of the reactants (changing its concentration) and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.

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3 years ago
Distinguish between sugar and non-sugar with examples.
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Answer:

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3 0
3 years ago
3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
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Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

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