(0,-4) graph the vertex

Maria has a cell phone and she gets charged for data each month. She is

aliina [53]

If it costs $12.5 for every GB and we use 8 then 12.5*8=$100. So if our flat rate now is $70 we would loose 100-70=$30

So Maria would loose $30 a month if she pays per GB

7 0

3 years ago

BRAINLIEST + 25 POINTS

Zarrin [17]

Take your graph and turn it counterclockwise 90°, 3 times (which equals 270°).

Let the horizontal line represent the x-axis and the vertical line represent the y-axis. What are the new coordinates of the image? J'(2, 6), M'(-1, 5)

Answer: C

7 0

4 years ago

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Charles runs 1/4 mile in 10 minutes. How long will it take him to run 1 1/2 miles?

Tema [17]

Since Charles runs a 1/4 mile in 10 minutes, and 1/4 goes into 1 1/2 6 times, the answer is 10*6, which is 60.

5 0

4 years ago

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Use the quadratic formula to solve the equation. 2x2−6x+1=0 Enter your answers, in simplified radical form, in the boxes. x = or

kodGreya [7K]

To solve this problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the exercise above:
2x²−6x+1=0
2. The quadratic equation is:
x=[-b±√(b²-4ac)]/2a
Where:
a=2
b=-6
c=1
3. When you substitute these values into the quadratic equation, you obtain:
x=3/2-√(7)/2
x=3/2+√(7)/2

5 0

3 years ago

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You know how to play 21 songs on your guitar. (a) If you want to choose 8 of the songs to make a setlist to play for a small gat

UNO [17]

Answer:

(a) 8,204,716,800

(b) 5,985

Step-by-step explanation:

Combinations and Permutations

Combinatorics is the part of the discrete mathematics that studies the enumeration of groups or sorting of a determined number of elements. The concept of combinations is tied to the different forms to group elements where the order of their arrangements is not important or does not differentiate from the very same set of elements picked in a different order.

The concept of combinations is tied to the differents forms to group elements where the order of their arrangements is not important or does not differentiate from the very same set of elements picked in different order.

On the other hand, permutations or variations are sets selected in a specific order and another set with the same element but in different order is considered a different set.

If we have n elements available to pick from in sets of m elements each, there can be C(n,m) different combinations, and it's given by

$\displaystyle C(n,m)=\frac{n!}{m!(n-m)!}$

Similarly the number of permutations is given by

$\displaystyle P(n,m)=\frac{n!}{(n-m)!}$

(a) I have n=21 songs to pick from and I want to choose m=8 of them where the order matters, so it's a permutation:

$\displaystyle P(21,8)=\frac{21!}{(13)!}=\frac{51,090,942,171,709,440,000}{6,227,020,800}=8,204,716,800$

I can make more than 8 billion different setlists

(b) To choose m=4 songs from n=21 songs where the order does not matter, we compute the combination

$\displaystyle C(21,4)=\frac{21!}{4!(17)!}=\frac{21\cdot 20\cdot 19\cdot 18\cdot 17!}{4\cdot 3\cdot 2\cdot 1(17)!}$

$\displaystyle C(21,4)=\frac{143,640}{24}=5,985$

I can make almost 6,000 sets of 4 songs

5 0

3 years ago