Question

PLEASE HELP ASAP are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?​

Answer 1

Answer:

To find the inverse of:

$f (x)=\dfrac{4}{x-2}-1$

Set the function to y:

$\implies y=\dfrac{4}{x-2}-1$

Rearrange to make x the subject:

$\implies y+1=\dfrac{4}{x-2}$

$\implies (y+1)(x-2)=4$

$\implies xy-2y+x-2=4$

$\implies xy+x=2y+6$

$\implies x(y+1)=2y+6$

$\implies x=\dfrac{2y+6}{y+1}$

Swap x and y:

$\implies y=\dfrac{2x+6}{x+1}$

Change y to the inverse of the function sign:

$\implies f$$\:^{-1}(x)=\dfrac{2x+6}{x+1}$

Rewrite g(x) as a fraction:

$g(x)=\dfrac{3}{x+2}-2$

$\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2x-4}{x+2}$

$\implies g(x)=-\dfrac{2x+1}{x+2}$

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other