34.
(a) A. x < 4
(b) p > 1
(c) y <span>≤ 2.8
I love solving inequalities. I hope you find this answer the most helpful! :)</span>
Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>![\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D%20%5C%5C%3D%28%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D%5Cfrac%7B3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2y%7D%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
</em>
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<em>Option D is right.</em>
U can find the reciprocal of a number by flipping the number.
example : the reciprocal of 1/5 is 5/1....the reciprocal of 2/3 = 3/2.
the reciprocal of x = 2/7.....that means x = 7/2
5 / (7/2) = when dividing fractions, flip what u r dividing by, then multiply
5 * 2/7 =
10/7 or 1 3/7 <==
13/5 or 2 3/5 by the way nice profile picture
Answer:
He will make $88 more a week then he did before.
Step-by-step explanation:
10% of $22 is 2.2.
2.2*40=88
