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3 years ago

Collision practice

Physics

1 answer:

NikAS [45]3 years ago

6 0

Answer:

$v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}$

Explanation:

Using the Law of Conservation of Momentum, we can set up the following equation:

$m_2v_2-m_1v_1=m_fv_f$ , where $m_1v_1$ is Bruce's momentum and $m_2v_2$ .

Plugging in given values, we get:

$90\cdot7-45\cdot2=(90+45)v_f, \\v_f=\frac{540}{135}=\fbox{$4\:\mathrm{m/s}$}$ .

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