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amid [387]
3 years ago
11

Which of the following is not true? A) The energy of the sun comes from nuclear fusion. B) The fuel for nuclear fusion comes fr

om sea water. C) The current nuclear power industry uses nuclear fission. D) When fusion occurs the final products have less mass than the initial products. E) Nuclear fission requires extremely high energy because positively charged particles must overcome their mutual repulsion.
Physics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

Option B) The fuel for nuclear fusion comes from sea water

Explanation:

Nuclear fusion can not be carried out by using any type of water as water is composed of stable water molecules (H_{2}O which is quite difficult to be decayed by any simple method.

Moreover, fusion reactions demands the combination of nuclei of lighter elements for which it makes use of the heavy isotopes of Hydrogen that are Deuterium and Tritium as fuel to carry out the nuclear fusion.

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A coin is dropped from a height of 188 meters. Neglecting air resistance, how much time (in seconds) was the coin in the air?
Marina CMI [18]

Answer:

t=6.19s

Explanation:

With a initial velocity is zero, kinematics equation is:

y=1/2*g*t^2

t=\sqrt{2y/g}=\sqrt{2*188/9.81}=6.19s

8 0
3 years ago
Quentin is playing baseball and is batting. He swings and hits the ball sending it flying to the outfield. Which is greater- the
Bess [88]

Answer:

The force of the ball on the bat is same as the force of the bat on the ball.  

Explanation:

A bat hits the ball and the ball moves to the out filed.

According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.  

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.  

5 0
3 years ago
If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Oksanka [162]

The fraction of the tensile strength which is the stress on the femur is 1.4%.

<h3>What is Tensile strength?</h3>

This is defined as the amount of load or stress that a material can handle before it stretches and breaks.

The femur which is located in the thigh is the largest bone in the body and it exerts a fraction of 1.4% tensile strength through the stress encountered on the femur when the man stands with one leg.

Read more about Tensile strength here brainly.com/question/25748369

5 0
2 years ago
A 750 g air-track glider attached to a spring with spring constant 14.0 N/m is sitting at rest on a frictionless air track. A 20
alexandr402 [8]

Answer:

the amplitude of  the subsequent oscillations is 0.11  m

the period of the subsequent oscillations is 1.94 s

Explanation:

given Information:

the mass of air-track glider, m_{1} = 750 g = 0.75 kg

spring constant, k = 13.0 N/m

the mass of glider, m_{2} = 200 g = 0.2 kg

the speed of glider,  v_{2} = 170 cm/s = 1.7 m/s

the amplitude of  the subsequent oscillations is A = 0.11  m

according to mechanical enery equation, we have

A = \sqrt{\frac{m_{1} +m_{2} }{k} }v_{f}

where

A is the amplitude and  v_{f} is the final speed.

to find v_{f}, we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.

P_{f} = P_{i}

(m_{1} +m_{2} )v_{f} = m_{1} v_{1} +m_{2}v_{2}

v_{1} = 0, thus

(0.75+0.2)v_{f} = (0.75)(0)+(0.2)(1.7)

0.95 v_{f} = 0.34

v_{f} = 0.36 m/s

Now we can calculate the amplitude

A = \sqrt{\frac{0.75 +0.2 }{10} }0.36

A = 0.11  m

the period of the subsequent oscillations is T = 1.94 s

the equation for period is

T = 2π\sqrt{\frac{m_{1}+m_{2}  }{k} }

T = 2π\sqrt{\frac{0.75+0.2  }{10} }

T = 1.94 s

7 0
3 years ago
A basketball is thrown horizontally with an initial speed of
storchak [24]

Answer:

1.35 m

Explanation:

Taking down to be positive, given:

Δx = Δy / tan 30.0º

v₀ₓ = 4.50 m/s

v₀ᵧ = 0 m/s

aₓ = 0 m/s²

aᵧ = 10 m/s²

Find: Δy

First, find the time it takes to land in terms of Δy.

Δy = v₀ t + ½ at²

Δy = (0 m/s) t + ½ (10 m/s) t²

Δy = 5t²

Next, find Δx in terms of t.

Δx = v₀ t + ½ at²

Δx = (4.50 m/s) t + ½ (0 m/s) t²

Δx = 4.50t

Substitute:

Δy = 5 (Δx / 4.50)²

20.25 Δy = 5 (Δx)²

4.05 Δy = (Δx)²

4.05 Δy = (Δy / tan 30.0º)²

4.05 Δy = 3 (Δy)²

1.35 = Δy

The basketball was thrown from an initial height of 1.35 m.

Graph: desmos.com/calculator/ujuzdo9xpr

8 0
3 years ago
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