WILL BE BRAINLIEST HELP!!!
1 answer:
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Answer:
(a) the tangential speed of a point at the edge is 3.14 m/s
(b) At a point halfway to the center of the disc, tangential speed is 1.571 m/s
Explanation:
Given;
angular speed of the disc, ω = 500 rev/min
diameter of the disc, 120 mm
radius of the disc, r = 60 mm = 0.06 m
(a) the tangential speed of a point at the edge is calculated as follows;
Tangential speed, v = ωr
v = 52.37 rad/s x 0.06 m
v = 3.14 m/s
(b) at the edge of the disc, the distance of the point = radius of the disc
at half-way to the center, the distance of the point = half the radius.
r₁ = ¹/₂r = 0.5 x 0.06 m = 0.03 m
The tangential velocity, v = ωr₁
v = 52.37 rad/s x 0.03 m
v = 1.571 m/s
Answer:
P= 168258.30696 Pa
Explanation:
Given that
Mass of water vapor m = 19.00 g
Volume of water vapor V = 2.00 L
Temperature of water vapor is T = 111°C
= 384K
Molar mass of water is M = 18.0148 g/mol
Number of moles are
n = m/M
= (1.90 g)/(18.0148 g/mol)
= 0.1054 mol
Pressure inside the container is
P= nRT/V
P= 168258.30696 Pa