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A mass-spring system oscillates with an amplitude of 4.60 cm. If the spring constant is 234 N/m and the mass is 524 g, determine

gizmo_the_mogwai [7]

Answer:

Mechanical energy, U = 0.247 Joules

Explanation:

Given that,

Spring constant of the spring, k = 234 N/m

Mass, m = 524 g = 0.524 kg

Amplitude, A = 4.6 cm = 0.046 m

To find,

The mechanical energy of the system.

Solution,

We know that the sum of kinetic energy and the potential energy is equal to its mechanical energy. In mass-spring system, it is given by :

$U=\dfrac{1}{2}kA^2$

$U=\dfrac{1}{2}\times 234\times (0.046)^2$

U = 0.247 Joules

So, the mechanical energy of the system is 0.247 Joules.

4 0

3 years ago

In nuclear fission, a nucleus splits roughly in half. (a) What is the potential 2.00 × 10−14 m from a fragment that has 46 proto

Valentin [98]

Answer:

electric potential is 3.31 × $10^{6}$ V

potential energy is 152 MeV

Explanation:

given data

fragment charge Q = 46 protons = 46 × 1.6 × $10^{-19}$ C

to find out

electric potential and potential energy

solution

we know here distance from fragment d = 2 × $10^{-14}$ m

and constant for electric force k that is 9 × $10^{9}$ N-m²/C²

so that we can find electric potential = kQ/d

electric potential = 9 × $10^{9}[/tex ×46 × 1.6 × [tex]10^{-19}$ / ( 2 × $10^{-14}$ )

electric potential = 3.31 × $10^{6}$ V

and

we know relation between electric potential and potential

that is V = U/q

so U will be = qV

now put all value

we get potential energy U

potential energy = 46 × 3.31 × $10^{6}$

potential energy = 1.52 × $10^{8}$ eV

so potential energy = 152 MeV

4 0

3 years ago

A car starts out traveling at 35 m/s. The car hits the brakes and decelerates at a rate of 3 m/s^2 for 5 seconds. What Distance

Ipatiy [6.2K]

Answer:

Time needed: 2.5 s
Distance covered: 31.3 m

Explanation:

I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by

v2f=v2i−2⋅a⋅d

Isolate d on one side of the equation and solve by plugging your values

d=v2i−v2f2a

d=(15.02−10.02)m2s−22⋅2.0ms−2

d=31.3 m

To get the time needed to reach this speed, i.e. 10.0 m/s, you can use the following equation

vf=vi−a⋅t, which will get you

t=vi−vfa

t=(15.0−10.0)ms2.0ms2=2.5 s

6 0

3 years ago

To summarize and analyze data with both a crosstabulation and charting, Excel typically pair

r-ruslan [8.4K]

Answer:

To summarize and analyze data with both a crosstabulation and charting, Excel typically pair PivotCharts with PivotTables (option b)

Explanation:

Pivot Tables allows us to deal with a high volume of data. This kind of tables are mainly designed to summarize, analyze and explore data in a simple way. Meanwhile, Pivot Charts gives the possibility to visualize the summarizing data provided in PivotTables, enabling the detection of trends, correlations,comparisons and so on. Because of that Pivot tables and pivot charts are usefull and complementary tools of Excel.

Summarizing, the proper option is b.

7 0

3 years ago

Which factors affect the strength of the electric force between two objects

Margaret [11]

<span>-- the product of the net charges on the objects;. -- the distance between the centers of their net charges. (Pretty much identical to the formula for gravitational force)</span>

8 0

3 years ago

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