All categories

3 years ago

According to Newton’s second law of motion, what is the force equal to?

Physics

2 answers:

kodGreya [7K]3 years ago

4 0

The answer to that is B.

marishachu [46]3 years ago

3 0

Newton's second law of motion states the following:

$F=ma$

In which $F$ is the force, $m$ is the mass, and $a$ is the acceleration of the object.

So, the answer is B.

You might be interested in

a racing car undergoes a uniform acceleration of 4.00m/s2. if the net force causing the acceleration is 3.00 times 10^3 N, what

yKpoI14uk [10]

Answer: 750Kg

Explanation:

Recall that force is the product of the mass M, of an object moving at a uniform acceleration.

i.e Force = Mass x Acceleration

In this case, Mass = ?

Force = 3.00 x 10^3 N = (3.00 x 1000N)

= 3000N

Uniform acceleration = 4.00m/s^2

Force = Mass x Acceleration

3000N = Mass x 4.00m/s^2

Mass = (3000N/4.00m/s^2)

Mass = 750Kg (The SI unit of mass is kilograms)

Thus, the mass of the car is 750Kg

4 0

3 years ago

Which two actions best demonstrate taking responsibility?

kow [346]

Answer:

Leading your people into the right direction, and always knowing what is best for you and your people.

Explanation:

6 0

3 years ago

A boy flies a kite with the string at a 30∘ angle to the horizontal. The tension in the string is 4.5 N. Part A Part complete Ho

zimovet [89]

Answer:

Work done is zero

Explanation:

given data

Angle of kite with horizontal = 30 degree

tension in the string = 4.5 N

WE KNOW THAT

Work = force * distance

horizontal force = $Tcos\theta = 4.5*cos30 = 3.89 N$

DISTANCE = 0 as boy stands still. therefore

work done = 3.89 *0 = 0

3 0

3 years ago

A car horn emits a frequency of 400 Hz. A car traveling at 20.0 m/s sounds the horn as it approaches a stationary pedestrian. Wh

Temka [501]

Answer:

The observed frequency by the pedestrian is 424 Hz.

Explanation:

Given;

frequency of the source, Fs = 400 Hz

speed of the car as it approaches the stationary observer, Vs = 20 m/s

Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.

The observed frequency is calculated as;

$F_s = F_o [\frac{v}{v_s + v} ] \\\\$

where;

F₀ is the observed frequency

v is the speed of sound in air = 340 m/s

$F_s = F_o [\frac{v}{v_s + v} ] \\\\400 = F_o [\frac{340}{20 + 340} ] \\\\400 = F_o (0.9444) \\\\F_o = \frac{400}{0.9444} \\\\F_o = 423.55 \ Hz \\$

F₀ ≅ 424 Hz.

Therefore, the observed frequency by the pedestrian is 424 Hz.

8 0

3 years ago

A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 41 feet per second. how high will the bal

maksim [4K]

Given: Height h = 6 ft or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.

Initial Velocity Vi = 41 ft/s g = -32.2 ft/s² acting downward

Require: Height h = ?

Formula: y = Vf² - Vi²/2g

y = 0 - (41 ft/s)²/2(-32.2 ft/s²)

y = -1,681 ft²/s²/(-64.4 ft/s²)

y = 26.10 ft

8 0

3 years ago