Hello :
<span>the parabola's equation is : f(x) = a(x+3)²-1
</span><span>the coefficient of the squared expression in the parabola's equation is : a
but ; f(4) = 0
0 = a(4+3)²-1
49a-1=0.....a=1/49
f(x) = 1/49(x-3)²-2</span>
Answer:
glucose that is what i think but it looks not right for your letter.
Step-by-step explanation:
Your answer will be 2 2/4. If you want it simplified it will be 2 1/2
Answer:
-1701
Step-by-step explanation:
The recursion relation tells you each term of the sequence is -3 times the previous term. Then the first 6 terms are ...
7, -21, 63, -189, 567, -1701
The value of f(6) is -1701.
_____
<em>Additional comment</em>
The explicit formula for a geometric sequence with first term 7 and common ratio -3 is ...
f(n) = 7×(-3)^(n-1)
Then f(6) is ...
f(6) = 7×(-3)^5 = 7×(-243) = -1701
