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Olin [163]
3 years ago
15

50 POINTS!!! Word problem.

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
4 0
Let d = # of dimes
Let q = # of quarters
45 = d + q
.1d + .25q = 8.40
Then we can use the substitution method and make it so that d = 45 - q.
Then plug in the value for d into the second equation.
.1(45-q)+.25(q)=8.40
4.5-.1q+.25q=8.40
4.5+.15q = 8.40
.15q = 3.90
q = 26
d = 45 - 26 = 19
26 quarters
19 dimes
SpyIntel [72]3 years ago
4 0

Answer:

Step-by-step explanation:

Let d = # of dimes

Let q = # of quarters

45 = d + q

.1d + .25q = 8.40

Then we can use the substitution method and make it so that d = 45 - q.

Then plug in the value for d into the second equation.

.1(45-q)+.25(q)=8.40

4.5-.1q+.25q=8.40

4.5+.15q = 8.40

.15q = 3.90

q = 26

d = 45 - 26 = 19

26 quarters

19 dimes

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The Torrence family has a rectangular, in-ground pool in their yard. It holds 1700 ft of water. If it is 17 ft wide and 4 ft dee
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aleksley [76]

Answer:

Step-by-step explanation:

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Equating the resulting expression to each end point.

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5 0
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Read 2 more answers
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