The easiest way to solve this is by elimination.
3x - y = 6
6x + y = 21
Since you have a negative and positive y with the same coefficients (1), they cancel, and you add the other terms so it would look like:
9x = 27
Then solving for x leaves you with x = 3
Then you take the x value of three and plug it into to either of the equations, so
3(3) - y = 6
9 - y = 6
subtracting 9
-y = -3
then dividing by -1
y = 3
so the solution is x = 3 y = 3 or (3,3)
Answer:
6x - 3
Step-by-step explanation:
2(x-3) + 4x + 3
= 2x - 6 + 4x + 3 (Multiply out)
= 2x + 4x - 6 + 3 (Rearrange)
= 6x - 3
Huh? Is their a picture or anything else that goes with that question?
