Answer:
72.51
Step-by-step explanation:
Given that :
Lab score % = 23%
Each Major test % = 22.5%
Final exam % = 32%
Score :
Lab score = 96
First Major test = 64
Second major test = 62
Final exam = 69
Hence,
Weighted average = Σ(weight % * score)
Weighted average = Σweight_1*score_1 +.. Weight_n * score_n)
(0.23 * 96) + (0.225 * 64) + (0.225 * 62) + (0.32 * 69) = 72.51
Answer:
125/42
Step-by-step explanation:
15/7 + 2/3 + 1/6
90/42 + 28/42 + 7/42
125/42
2.976
Answer:
The north campus had 
while the south campus had 
.
Step-by-step explanation:
The question stated that there are 
students in the merged campus. That's the sum of the number of students in the north and the south campus before the merger.
Let 
denote the number of students in the north campus before the merger. The other 
students would all belong to the south campus before the merger.
Before the merger, 
of the students of the north campus are of music majors. In terms of , that's 
students.
On the other hand, 
of the students of the south campus are of music majors. That corresponds to 
students.
With a similar logic, the number of music students in the merged east campus will be 
.
The question implies that the sum of students in the two campuses should be equal to the number of music students in the east campus. That is:
.
Solve for :
.
In other words, there are students in the north campus and 
students in the south campus before the merger.
Answer:
d = √13
Step-by-step explanation:
d = √((x2 - x1)² + (y2 - y1)²)
points: (-3, 8) & (-1, 5)
d = √((-1 - -3)²+(5 - 8)²)
d = √(2)²+(-3)²
d =√(4 + 9)
d = √13
