Answer:
(8-(3+b))3
Step-by-step explanation:
first of all, we have to variables, 3 and b that we are told to add
that is, 3+b
we are now told to subtract the answer from 8
that is 8 minis the answer
= 8- (3+b)
lastly we triple the answer to give
(8-(3+b)3
or
3(8-(3+b)
Answer:
Ste-by-step explanation:bf=7x-10 bc=4x-29
Answer:
Step-by-step explanation:
27^1/3
27 is cube root of 3
so it can also be written as (3)^3
∴ {(3)^3}^1/3
3 and 3 will get cancelled
so it will be 3^1
= 3
Answer:
Step-by-step explanation:
formula for area of parallelogram
= A=bh
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation

Solve for S(t):


The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:



There's no sugar in the water at the start, so (a) S(0) = 0, which gives

and so (b) the amount of sugar in the tank at time t is

As
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.