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3 years ago

5

a school news paper estimates that their academic team will win 25 out of 30 matches for the season. After 15 matches, they have

won 12. If the team continues winning at this rate, what will be the percent error of the newspapers estimate once the season is over?

1 answer:

san4es73 [151]3 years ago

5 0

27% hope this helps:)

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Simplify completely the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.

Elanso [62]

Answer:

(A) $3x^3+5x+2$

Step-by-step explanation:

To Simplify: The quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.

Solution: The given statement can be easily rewritten as:

$The quantity 3 times x to the 4th power=3x^4$ ,

$5 times x to the 2nd power=5x^2$ and

$2 times x =2x$

Thus, according to the statement, the expression can be written as:

$\frac{3x^4+5x^2+2x}{x}$

⇒ $3x^3+5x+2$

which is the required simplified expression.

Thus,option A is correct.

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3 years ago

A company spent 35% of its annual budget building a new machine. How much of the

Yuliya22 [10]

$8,750
(25000*.35)
Multiply

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2 years ago

Simplify the trigonometric expression.

Natasha_Volkova [10]

First we are going to find the common denominator of both fractions. To do that, we are going to multiply their denominators:
$(1+sin \alpha )(1-sin \alpha )=1-sin^2 \alpha$

Now we can rewrite our expression using the common denominator:
$\frac{1-sin \alpha }{1-sin^2 \alpha } + \frac{1+sin \alpha }{1-sin^2 \alpha} = \frac{2}{1-sin^2 \alpha}$

Finally, we can use the trig identities: $1-sin^2 \alpha =cos^2 \alpha$ and $sec \alpha = \frac{1}{cos \alpha }$ to simplify our trig expression:
$\frac{2}{cos^2\alpha}=2sec^2 \alpha$

We can conclude that the correct answer is the fourth one.

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3 years ago

Read 2 more answers

Please help fast will give brainliest

antoniya [11.8K]

Answer:

THE ANSWER IS C

Step-by-step explanation:

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3 years ago

Read 2 more answers

A production process fills containers by weight. Weights of containers are approximately normally distributed. Historically, the

forsale [732]

Answer:

option (c) n = 201

Step-by-step explanation:

Data provided in the question:

Standard deviation, s = 5.5 ounce

Confidence level = 99%

Length of confidence interval = 2 ounces

Therefore,

margin of error, E = (Length of confidence interval ) ÷ 2

= 2 ÷ 2

= 1 ounce

Now,

E = $\frac{zs}{\sqrt n}$

here,

z = 2.58 for 99% confidence interval

n = sample size

thus,

1 = $\frac{2.58\times5.5}{\sqrt n}$

or

n = (2.58 × 5.5)²

or

n = 201.3561 ≈ 201

Hence,

option (c) n = 201

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3 years ago