<h3>
Answer: Only first two are exponential growth function and last three functions are exponential decay functions.</h3>
Step-by-step explanation: We need to describe exponential growth or decay for the given functions.
The standard exponential function equation is
.
Where a is the initial value and b is the growth factor.
Note: If value of b > 1, it would be an exponential growth and if b < 1, it would be an exponential decay.
Let us check them one by one.
=> 
=>
.
Value of b is 1.008 > 1, therefor it's an exponential growth function.
y=250(1+0.004)^t, also have b>1 therefor it's an exponential growth function.
All other functions has b values less than 1, therefore only first two are exponential growth function and last three functions are exponential decay functions.
Answer: h=7
Step-by-step explanation:
By definition the function in vertex form is:

Where (h,k) is the vertex of the parabola.
You must group the terms that contain the same variable in the function:

Complete the square as following:

Now you must rewrite it as following:

Then:
h=7
Answer:
5 days
Step-by-step explanation:
1/2 + 1/2 = 3 (2 days) times by 2 makes it 4 days and finally 5th day 7 1/2
no it is not simplified because there are two y values