3/4=8/x-1
3/4+4/4=8/x
7/4=8/x
7x/4=8
7x=32
x=32/7
Answer:
i ) $96120
ii ) Singular adult fee in 2012: $186.91
Step-by-step explanation:
( i )
To find the costs of all 560 peoples you:
Multiply the amount of people by the fee,
440 × 198 = $87120
120 × 120 = $9000
Add these go get the sum of member fees: $96120
( ii )
First calculate what 1% of the adult fee would be:
198 ÷ 100 = 1.98 = 1%
Then calculate what 0.1% of the fee:
1.98 ÷ 10 = 0.198 = 0.1%
Now multiply 5 by the value of 1% to get 5% :
5 × 1.98 = 9.9
Then multiply 6 by the 0.1% to get 0.6% :
0.198 × 6 = 1.188
Add these numbers together to get:
1.188 + 9.9 = $11.088 = 5.6%
Due to the fact this question is referring to money we will round this number 2 decimal places (as money does not exceed 2dp)
$11.09
We now subtract this from the 2013 fee to find out the 2012 fee
$198 - $11.09 = $186.91
$186.91 was the cost of a singular adult fee in 2012
Answer:
y=-5x+1
Step-by-step explanation:
y-y1=m(x-x1)
y-(-9)=-5(x-2)
y+9=-5x+10
y=-5x+10-9
y=-5x+1
The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
<h3>
What is magnitude of earthquake
?</h3>
Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.
An earthquake with a magnitude of about 2. 0 or less is called a micro-earthquake and not felt usually.The intensity of an earthquake with a magnitude of 2.
Let the intensity of this earthquake is <em>n </em>times greater than the intensity of an a standard earthquake. Thus the intensity of standard earthquake can be given as,

If the magnitude would be 3 then the intensity would be,

It would be 1000 times greater than the standard earthquake and so on.
Thus, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
Learn more about the magnitude of earthquake here;
brainly.com/question/18109453
Answer: 0.70
Step-by-step explanation:
Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:
x 0 1 2 3 4 5
P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05
Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_

Hence, the required probability = 0.70