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valkas [14]
3 years ago
8

HELP ASAPPP!!! !!!! PLEASE

Mathematics
2 answers:
Yuri [45]3 years ago
7 0
The answer is A. Because it is in the thousands
Harlamova29_29 [7]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

for decimals, you start with tenths, so it would be thousandths

You might be interested in
Please help on this problem
Harlamova29_29 [7]
Answer: EP is 12 and EO is about 10.91.

To find the length of EP, we can use the Pythagorean Theorem with the 2 legs of the right triangle it would form, EC and CP. CP would be 5 because it is the midpoint of the side.

5^2 + (EP)^2 = 13^2
EP = 12

Now, to find EO, we write and solve another Pythagorean Theorem equation using 12 for EP.

5^2 + (EO)^2 = 12^2
EO equals the square root of 119 or about 10.91.
6 0
3 years ago
Find the inverse of square root f(n) = n – 3.
pogonyaev

Answer:

f'(n) = n + 3

Step-by-step explanation:

Given

f(n) = n - 3

Required

The inverse

f(n) = n - 3

Replace f(n) with y

y = n - 3

Swap positions of y and n

n = y - 3

Make y the subject

y = n + 3

Replace y with f'(n)

f'(n) = n + 3

4 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
I need a answer please
8_murik_8 [283]

Answer: 6/24 ????????????

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
It takes two painters 4 days to complete a job. How long does does 1 painter take for the same job?
yulyashka [42]
It will take 8 days
7 0
2 years ago
Read 2 more answers
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