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Harlamova29_29 [7]
4 years ago
9

Find the volume of a right circular cone that has a height of 8.4 m and a base with a radius of 2.2 m. Round your answer to the

nearest tenth of a cubic meter.
Mathematics
2 answers:
Wittaler [7]4 years ago
8 0

Answer:

42.6m^3

Step-by-step explanation:

Volume of a Cone =\frac{1}{3}\pi r^2 h

Height, h=8.4m

Radius,r =2.2m

Therefore:

Volume of the Right Circular Cone =\frac{1}{3}* \pi *2.2^2 *8.4=42.57m^3

Therefore the volume of the cone is 42.6m^3 to the nearest tenth.

zimovet [89]4 years ago
3 0

Answer:

The volume of the cone is 42.6 m^3

Step-by-step explanation:

The volume of a cone is given by the area of the base multiplied by the height of the cone and divided by three. The base is a circle, so it's area is computed by the following:

Abase = pi(r^2) = 3.14(2.2^2) = 15.2 m^2

We can then compute the volume of the cone that is:

Vcone = Abase*h/3 = 15.2*8.4/3 = 42.56 m^3

The volume of the cone is 42.6 m^3

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Answer:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

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Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

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we have

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substitute

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The domain is the interval (0,5)

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