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2 years ago

Please help with this precalc!!! i desperately need help

Mathematics

1 answer:

Paladinen [302]2 years ago

6 0

Step-by-step explanation:

4 is the A or Ampltiude

To find the period set it equal to 2 pi/B

$\frac{2\pi}{b} = \frac{6}{1}$

$\frac{b}{2\pi} = \frac{1}{6}$

$\frac{2\pi}{6}$

$\frac{\pi}{3}$

There is no phase shift

The midline or d or vertical shift is 1.

Our equation for 8 is

$4 \sin( \frac{\pi}{6} x) + 1$

9.Use sin function. The a value is 2 or -2 your choice.

Set up the period equal to the equation

$\frac{2\pi}{b} = \frac{\pi}{3}$

$\frac{b}{2\pi} = \frac{3}{\pi}$

$b = \frac{3}{\pi} \times 2\pi$

Which equal 6.

B=6

There is no C and the D and Vertical Shift is 1.

Our equation is

$2 \sin(6x) + 1$

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3 years ago

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A bucket is leaking.After 3hr the bucket has leaked 3/4 of an ounce.How many ounces per hour is the bucket leaking 3/4oz-3hr= 3/

777dan777 [17]

Answer: 1/4 ounces per hour

Step-by-step explanation:

In the 3 hours that the bucket has leaked, it has lost 3/4 ounces.

The rate at which it is leaking is therefore:

= 3/4 / 3

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2 years ago

100 points!!! Pre calculus. I need helpppppppppp

Fantom [35]

Answer:

We have function,

$y = 3 - 6 \sin {}^{} (2x + \frac{\pi}{2} )$

Standard Form of Sinusoid is

$y = - 6 \sin(2x + \frac{\pi}{2} ) + 3$

Which corresponds to

$y = a \sin(b(x + c)) + d$

where a is the amplitude

2pi/b is the period

c is phase shift

d is vertical shift or midline.

In the equation equation, we must factor out 2 so we get

$y = - 6(2(x + \frac{\pi}{4} )) + 3$

Also remeber a and b is always positive

So now let answer the questions.

a. The period is

$\frac{2\pi}{ |b| }$

$\frac{2\pi}{ |2| } = \pi$

So the period is pi radians.

b. Amplitude is

$| - 6| = 6$

Amplitude is 6.

c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.

So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].

D. Plug in 0 for x.

$3 - 6 \sin((2(0) + \frac{\pi}{2} )$