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lesya [120]
3 years ago
6

A store donated cases of crayons to a day care center. Each case holds 24 boxes of crayons; each box holds 8 crayons. How many c

rayons did the center receive?​
Mathematics
2 answers:
posledela3 years ago
4 0

Answer:

They recieved 192 crayons?

siniylev [52]3 years ago
4 0

Answer:

The Answer Is 192

Step-by-step explanation:

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PLEASE HELP!!!!!!<br><br> I really need help on this! It's due today and I'm kinda late on it!!
Margaret [11]

Answer:

1.not 2×4 is 2+4 answer should be 6x⁶

2.not 3+4 is 3×4 answer should be 12a⁷

3.miss 1 should x^(6+1+3) should be x¹⁰

4.base different, and just become 81×8=648

3 0
3 years ago
Algebra isn’t my best subject, please help
kogti [31]

The Distributive property states that when we have the statement a(b + c), we can "distribute" the a by multiplying a times both terms that are inside the parenthses.

So in this problem, 2(5 + 7) can be simplified by distributing the

2 through both terms that are inside the set of parenthses.

So we have (2 · 5) + (2 · 7).

8 0
3 years ago
Please help me interpret the p-value!
alexandr402 [8]

The correct interpretation of the p-value is given by:

B If the average battery life really is 5 hours, then a sample of 10 observations having a sample mean of 4.25 hours or lower would only occur about 3.8% of the line.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows:

  • For a left-tailed test, it is the area under the normal curve to the left of z, which is the p-value of z.
  • For a right-tailed test, it is the area under the normal curve to the right of z, which is 1 subtracted by the p-value of z.
  • For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is 2 multiplied by 1 subtracted by the p-value of z, which means that the p-value for a two-tailed test is twice the p-value of a one-tailed test.

In this problem, a left-tailed test is used, as we are testing if the mean is less than 5 hours.

The sample mean from the 10 times was of 4.25, and the p-value is of 0.038, which means that the area to the left of Z under the normal curve is of 0.038, that is, a sample mean of 4.25 hours or lower would only occur about 3.8% of the line, hence option B is correct.

You can learn more about p-values at brainly.com/question/13873630

3 0
2 years ago
Solving for matrices
muminat

Answer:

D

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)

Multiply the first row by 5, the second row by -3 and add these two rows:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

Now multiply  the third equation by 26 and add it to the second row:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

From the third equation

z=\dfrac{90}{45}=2.

Substitute z=2 into the second equation:

-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.

Now substitute z=2 and y=5 into the first equation:

3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.

The solution is (1,5,2)

4 0
3 years ago
Can someone plz help Me?
hammer [34]

Answer:

A

^{}

3 0
2 years ago
Read 2 more answers
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