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2 years ago

Find the area of the semicircle. Round your answer to the nearest hundredth. PLEASEE HELPP

Mathematics

1 answer:

trapecia [35]2 years ago

7 0

Answer:

Area of semicircle = 226.08 in²

Step-by-step explanation:

Diameter of semicircle = 24 in

We need to find area of semicircle.

The formula used to find area of semicircle is: $Area=\frac{\pi r^2}{2}$

First we will find radius

We know that: radius = diameter/2 = 24/2 = 12

Now, finding area

$Area=\frac{\pi r^2}{2}\\Area=\frac{3.14\times (12)^2}{2}\\Area=\frac{452.16}{2}\\Area=226.08\:in^2$

So, Area of semicircle = 226.08 in²

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Quincy was stuck inside during an afternoon rainstorm. He spent 20 minutes reading books, 18 minutes eating lunch, 12 minutes wa

Scorpion4ik [409]

Answer:

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Step-by-step explanation:

6 0

2 years ago

Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,

alexgriva [62]

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

$\frac{sin(B)}{b} = \frac{sin(C)}{c}$

$\frac{sin(B)}{24} = \frac{sin(82)}{29}$

$sin(B)*29 = sin(82)*24$

$\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}$

$sin(B) = \frac{sin(82)*24}{29}$

$sin(B) = 0.8195$

$B = sin^{-1}(0.8195)$

$B = 55.0$

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

$\frac{a}{sin(43)43} = \frac{24}{sin(55)}$

Cross multiply

$a*sin(55) = 25*sin(43)$

$a = \frac{25*sin(43)}{sin(53)}$

$a = 20$ (approximated)

8 0

2 years ago

Math work...HELPPPP!

anzhelika [568]

1/6 unit- 4
1/8 unit- 3

5 0

2 years ago

Read 2 more answers

(MC 02.03) If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A

Soloha48 [4]

A' would lie on point A (-4 , 1)

Step-by-step explanation:

Let us revise some transformations

1. If point (x , y) reflected across the x-axis , then its image is (x , -y)

2. If point (x , y) reflected across the y-axis , then its image is (-x , y)

3. If point (x , y) rotated about the origin by angle 180°, then its image

is (-x , -y)

Parallelogram ABCD was reflected over the y-axis, reflected over the

x-axis, and rotated 180°

We need to know where would point A' lie

∵ The coordinates of point A are (-4 , 1)

∵ The parallelogram is reflected over x-axis

∴ The sign of y-coordinate of point A changed to opposite

∴ The image of point A is (-4 , -1)

∵ The parallelogram then reflected over the y-axis

∴ The sign of x-coordinate of point (-4 , -1) changed to opposite

∴ The image of point (-4 , -1) is (4 , -1)

∵ The parallelogram then rotated 180°

∴ The signs of the x-coordinate and the y-coordinate of point (4 , -1)

changed to opposite

∴ The image (4 , -1) is (-4 , 1)

∴ A' is (-4 , 1)

∵ Point A is (-4 , 1)

∴ A' would lie on point A

A' would lie on point A (-4 , 1)

Learn more:

You can learn more about rotation in brainly.com/question/9720317

#LearnwithBrainly

3 0

3 years ago

Solve. 6x+1=4x+5. Please show work!!!

stich3 [128]

To solve, combine like terms:
6x+1=4x+5
2x+1=5
2x=4
x=2

7 0

3 years ago

Read 2 more answers