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Ronch [10]
3 years ago
15

What is the product of 2.5 x 10 power of -15 and 3.9 x 10 to the power of 26

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0
For the first one its 2500000000000000 and the second one is too big a number to know
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Please help me solve this math problem
pochemuha

Answer:

 (b)

Step-by-step explanation:

A suitable calculator or spreadsheet can find the matrix product for you. Here, the answer choices differ in their upper left term, so we can determine the correct choice by finding the value of that term. It is the dot product of the first row of B and the first column of A.

  (5)(3) +(7)(3) +(3)(2) = 15 +21 +6 = 42

This matches choice B.

7 0
2 years ago
What are the values of x ?
Vera_Pavlovna [14]

Answer:

50

Step-by-step explanation:

since they are parallel then 2x+6=106

so subtract 6 from each side so it's 2x = 100

then divide each since by 2

so x= 50

7 0
3 years ago
Read 2 more answers
What are the domain and range and asympote of h(x)=6^x -4?
Arturiano [62]
Bksnsskbd fcnfkdn sishfmdibaub subneibfs uh a
8 0
3 years ago
I need help that is simple enough explnation
velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
2 years ago
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